Question

250tThe population of Sasquatch in Salt Lake County was modeled by the function P(t)wheret + 25t = 0 represents the year 1803. When were there fewer than 150 Sasquatch in Salt Lake County?Present your answer, to the nearest whole year, in interval notation.There were fewer than 150 Sasquatch in Salt Lake City between the years

Answer 1

Solution

Given the population function to be;

$P(t)=\frac{250t}{t+25}$

When P(t) = 150

$\begin{gathered} \Rightarrow\frac{250t}{t+25}=150 \\ \\ \Rightarrow250t=150(t+25) \\ \\ \Rightarrow250t=150t+3750 \\ \\ \Rightarrow250t-150t=3750 \\ \\ \Rightarrow100t=3750 \\ \\ \Rightarrow t=37.5\approx38 \end{gathered}$

1803 + 38 = 1841.

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Answer 2

In 1841 there are fewer than 150 Sasquatch in Salt Lake County.

What is an expression?

Mathematical expression is defined as the collection of the numbers variables and functions by using operations like addition, subtraction, multiplication, and division.

Given that;

The population of Sasquatch in Salt Lake County was modeled by the function is;

⇒ P (t) = 250t / (t + 25)

Now,

Since, The population of Sasquatch in Salt Lake County was modeled by the function is;

⇒ P (t) = 250t / (t + 25)

Since, There are fewer than 150 Sasquatch in Salt Lake County.

So, We can formulate;

⇒ 250t / (t + 25) < 150

⇒ 250t < 150t + 3,750

⇒ 250t - 150t < 3,750

⇒ 100t < 3,750

⇒ t < 37.50

⇒ t ≈ 38

Thus, The interval of time for Salt Lake City between the years ;

⇒ 1803 + 38 = 1841

Therefore, In 1841 there are fewer than 150 Sasquatch in Salt Lake County.

Learn more about the mathematical expression visit:

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