Explain the difference between an inequality with OR and an inequality with AND.

1 answer:

4 0

Inequality with OR: We use OR when you have two or more cases that could or not happen at the same time, for example with inequalities when you have an OR you use the union of the sets given by the inequalities. for example if we have the following two inequalities

$x\ge1\text{ or x}\leq0$

it will represent the union of the set of numbers that are greater than one with the set of the numbers that are less than zero.

Inequality with AND: We use AND when you need that all the conditions holds at the same time (here is not accepted that only one holds) for example with inequalities when you have AND you need to use the intersection of the sets given by the inequalities. For example:

$x\ge2\text{ AND x}\leq10$

will represent the intersection of the set of number that are greater than two and less than ten AT THE SAME TIME

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a chess player played 136 games total. If he won 56 of the games, what is the ratio of games he lost to games he won?

wolverine [178]

Answer:

80:56

Step-by-step explanation:

if you do 136-56, you get 80. therefore the number of games lost is 80. you already know he won 56, so the ratio is 80:56.

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A vertical right circular cylindrical tank has height h=8 feet high and diameter d=6 feet. It is full of kerosene weighing 50 po

Mariana [72]

Answer:

The work done to pump all of the kerosene from the tank to an outlet is $W=45238.9\: J$

Step-by-step explanation:

The work is defined by:

$W=\int dFdx$ (1)

The force here will be the product between the volume and the kerosene weighing, so we have :

$dF=\pi R^{2}dy*50$

This force will be in-lbs.

Where R is the radius (3 feet)

Then using (1), we have:

$W=\int \pi R^{2}dy*50(8-y)$

Here 8-y is a distance at some point of the tank. Now, to get the work done from the base to the top of the tank we will need to take integral from 0 to 8 feet.

$W=\int_{0}^{8} \pi 3^{2}dy*50(8-y)$