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fiasKO [112]
3 years ago
14

The age of a father is 2 less than 7 times the age of his son. In 3 years, the sum of their ages will be 52. If the son’s presen

t age is s years, which equation models this situation?
Mathematics
1 answer:
Butoxors [25]3 years ago
6 0
S = the son's age
f = the father's age

In three years ,the sum of their ages will be 52.

(s + 3) + (f + 3) = 52 

The age of a father is 2 less than 7 times the age of his son.

<span>7s - 2 = f
</span>
<span />
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Each statement describes a transformation of the graph of y= x. Which statement correctly describes the graph of yu x- 8?
tamaranim1 [39]

Answer:h

Step-by-step explanation:

H

4 0
3 years ago
In health class, students record the weights of the sandwiches they have for lunch. The weights are shown in the line plot below
Dvinal [7]
To find the average weight, you need to add all of the numbers and then divide them
I'll start off by doing this:
1/8+1/8 = 2/8
1/4+1/4+1/4+1/4 = 1
3/8+3/8 = 6/8
1/2+1/2 = 1
then I'll add them together:
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now we need to divide the amount of numbers. the amount of sandwiches weighted (10) will have to be divided
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4 0
3 years ago
A researcher compares the effectiveness of two different instructional methods for teaching electronics. A sample of 138 student
yan [13]

Answer:

The 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for the difference between population means is:

CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}

The information provided is as follows:

n_{1}= 138\\n_{2}=156\\\bar x_{1}=61\\\bar x_{2}=64.6\\\sigma_{1}=18.53\\\sigma_{2}=13.43

The critical value of <em>z</em> for 98% confidence level is,

z_{\alpha/2}=z_{0.02/2}=2.326

Compute the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 as follows:

CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}

     =(61-64.6)\pm 2.326\times\sqrt{\frac{(18.53)^{2}}{138}+\frac{(13.43)^{2}}{156}}\\\\=-3.6\pm 4.4404\\\\=(-8.0404, 0.8404)\\\\\approx (-8.04, 0.84)

Thus, the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

5 0
3 years ago
What is the value of x?
kari74 [83]

Answer:

4

Step-by-step explanation:

I took the quiz, here's proof

4 0
3 years ago
Find mFE<br> A) 52°<br> C) 76°<br> B) 93°<br> D) 112°
mixer [17]

Answer:

76 degrees

Step-by-step explanation:

GE = 180 since it is a straight line

GE = GR + FE

180 = 7x+6 +6x-8

Combine like terms

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Add 2 to each side

182 = 13x

Divide by 13

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14 =x

We want FE

FE = 6x-8

FE = 6(14) -8

    =84 -8

    =76

3 0
3 years ago
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