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MA_775_DIABLO [31]
3 years ago
14

Can someone help me answer these?

Mathematics
1 answer:
Romashka [77]3 years ago
4 0

Answer:

The Answer is as below:

Step-by-step explanation:

x      y = 3x + x     y = 2x - 3 + x

3     12            6

2     8            3

1     4            0

0     0           -3

-1    -4           -6

-2    -8           -9

-3  -12           -12

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Hey pls help !!! worth 25 points
amm1812

Start with the point-slope form: y-y_1 = m(x-x_1).

Then you substitue in the slope and coordinates from the point:

    y-5 = 2(x-(-7))

You don't do a lot of clean up to the form, with the exception of turning "minus negative 7" into "plus 7".

    y-5 = 2(x+7)

Thar be yer answer!

5 0
3 years ago
Olhe a imagem e responda
matrenka [14]

Answer:

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8 0
3 years ago
It says ( Find the length of the hypotenuse )<br> ~<br> Pls?<br> Thanks!
Mashcka [7]

Answer:

5

Step-by-step explanation:

In order to solve this problem, we need to use Pythagorem Theorem (a^2+b^2=c^2)

When using the pythagorem theorem the hypoteneuse would be the c^2 and the two other sides would be a and b (the order doesn't matter).

So, our formula would be:

4^2+3^2=c^2

Simplifies into:

25=c^2

In order to remove the exponent 2, we would have to square root both sides by 2. After doing so, you get the answer 5.

Hope this helps! :)

5 0
3 years ago
Read 2 more answers
On a popular television quiz show, contestants gain points for getting questions correct, and lose points for getting the answer
xenn [34]

Answer:

A

Step-by-step explanation:

200+150+150=500

500-500=0

5 0
3 years ago
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Calculate the amount of hcn that gives the lethal dose in a small laboratory room measuring 12.0 ft×15.0 ft×8.50ft.
Anarel [89]
Dimensions of the room in cm = 2.54 x 12 by 15 x 2.54 by 2.54 x 8.5 = 30.48 by 38.1 by 21.59

Volume of the room in cubic cm = 30.48 x 38.1 x 21.59 cubic cm = 25,072.21 cubic cm

Given that the density of air at room temperature is 0.00118g/cm^3, thus the mass of air in the room = 25,072.21 x 0.00118 = 29.59 g = 0.0296 kg

Given that the lethal dose of HCN is approximately 300 mg HCN per kilogram of air when inhaled, thus the <span>amount of HCN that gives the lethal dose in the small laboratory room is given by 300 x 0.0296 = 8.88 mg.</span>
7 0
3 years ago
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