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jekas [21]
3 years ago
9

If there is 1 birth every 11 seconds, how many births are there in 3 hours 43 minutes and 51 seconds

Mathematics
1 answer:
Grace [21]3 years ago
4 0
The answer would be 1221 as 3hours 43 minutes and 51 secs is 13431 secs and dividing that by 11 would give you 1221. hope that helped
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Jackie is selling packs of cookies for a fundraiser. Each box of cookies costs $6. She sells 12 boxes of cookies on Monday, 16 b
Tamiku [17]

Answer: 246

Step-by-step explanation:

Multiply each number by 6 then add all the numbers together. I think thats what it meant?

4 0
3 years ago
PLEASE HELP!!!!!!!!!!!!!!!!!<br><br> Solve.<br><br> −1/2x + 1/3 &gt; 3/5
Shtirlitz [24]
To solve this inequality, you must first isolate the term that includes the variable, which is -1/2x. This can be done by first subtracting 1/3 from both sides.

Before you can subtract 1/3 from 3/5, however, you must first convert the fractions to have common denominators.
A common denominator for 1/3 and 3/5 is 15. This is the LCM, least common multiple, of 3 and 5, making it the lowest possible common denominator.
Using this common denominator, 1/3 changes to 5/15 and 3/5 changes to 9/15.

Now we can subtract these equivalent fraction for 1/3, which is 5/15, from the fraction equivalent to 3/5, which is 9/15.
9/15 - 5/15 = 4/15
This fraction can't be simplified any further so this step is done.

Now the inequality is -1/2x > 4/15.
The next step is to isolate x by dividing both sides by -1/2.
An important note to remember when doing this step is that whenever dividing by a negative in inequalities, you must flip the inequality symbol.
In this case, that means dividing both sides by -1/2 and changing the greater than sign (>) to a less than sign (<).

-1/2x ÷ -1/2 = x

4/15 ÷ -1/2
When dividing fractions, find the reciprocal of the second fraction then multiply.
The reciprocal of -1/2 is -2/1, or -2 when simplified.
4/15 • -2 = -8/15

This means x < -8/15.
This has x isolated and the inequality simplified as far as possible.
That means this is the answer.

Answer:
x < -8/15

Hope this helps!
5 0
3 years ago
Please help me! 7x+6=?
wariber [46]

If we were to simplify this it would equal the same equation because this cannot be solved. Due to there being no like terms. We also need to know what x equals which there is no number given here to solve. Have a great day!

4 0
3 years ago
Can someone please explain to me how to work this out?
Ludmilka [50]

Answer:

B

Step-by-step explanation:

the way i work it out is if you take the product and power it to the third you can easily find out which answer is correct. another way, if you don't have a calculator is to look at the last digit in the number in the square root sign.

For example, 3 square root 64 equals 8. you would look at the 4 and try to find 3 numbers that end in 4 OR is divisible three times by the number. 64 is exactly divisible by 4 only 3 times so you know that it can't be 8.

hope this helps!

3 0
3 years ago
An explosion causes debris to rise vertically with an initial speed of 120 feet per second. The formula h equals negative 16 t s
Novay_Z [31]

Answer:

The debris will be at a height of 56 ft when time is <u>0.5 s and 7 s.</u>

Step-by-step explanation:

Given:

Initial speed of debris is, s=120\ ft/s

The height 'h' of the debris above the ground is given as:

h(t)=-16t^2+120t

As per question, h(t)=56\ ft. Therefore,

56=-16t^2+120t

Rewriting the above equation into a standard quadratic equation and solving for 't', we get:

-16t^2+120t-56=0\\\textrm{Dividing by -8 throughout, we get}\\\frac{-16}{-8}t^2+\frac{120}{-8}t-\frac{56}{-8}=0\\2t^2-15t+7=0

Using quadratic formula to solve for 't', we get:

t=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\t=\frac{-(-15)\pm \sqrt{(-15)^2-4(2)(7)}}{2(2)}\\\\t=\frac{15\pm \sqrt{225-56}}{4}\\\\t=\frac{15\pm\sqrt{169}}{4}\\\\t=\frac{15\pm 13}{4}\\\\t=\frac{15-13}{4}\ or\ t=\frac{15+13}{4}\\\\t=\frac{2}{4}\ or\ t=\frac{28}{4}\\\\t=0.5\ s\ or\ t=7\ s

Therefore, the debris will reach a height of 56 ft twice.

When time t=0.5\ s during the upward journey, the debris is at height of 56 ft.

Again after reaching maximum height, the debris falls back and at t=7\ s, the height is 56 ft.

5 0
3 years ago
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