Step-by-step explanation:
i)=
m=2/3
x=-3
y = 5
now
y=mx+c
or, 5 = 2/3× -3 + c
or, 5 = -2+c
c =7
now,
y= mx + c
or, y = 2/3×x+7
or, y = 2x/3+7
or, 3y = 2x+21
so, 3y-2x=21
equation would be 3y-2x=21.
now
ii)=
if slope of 3y-2x=21 and 2x-3y = 0 are same, they are parallel.
2x-3y = 0
2x = 3y
lets suppose x is 9
now
2x=3y
2×9 = 3y
or, 18 = 3y
so, y = 6
one coordinate would be (9,6) now
lets again suppose x is 3
2x=3y
2×3 = 3y
or, 6 = 3y
so, y = 2
another coordinate is (3,2)
now lets find slope
x1=9,y1=6
x2=3,y2=2
slope = (y2-y1)/(x2-x1)
= (2-6)/(3-9)
= -4/-6
= 2/3
Since, slope of 3y-2x=21 and 2x-3y has same slope 2/3, they are parallel.
Not completely sure but i think it is 16
Answer:
Step-by-step explanation:
5 red
15 black
10 white
altogether the is 30 marbles so that means it is 'out of' 30
and because the is 5 red it would be 5/30
and because the is 10 white it would be 10/30
that should be the answer but if you have to work the total all together then it would be 15/30
hope this helps :)
The diagonal fencing will be the hypotenuse of a right triangle with sides 120yds long so:
h=√2(120^2))
h=√28800 yd
And the surrounding fencing will just be four times the side length of 120yds so:
s=480yd
So the total fencing needed is:
f=480+√28800 yards
f≈649.71 yd (to nearest hundredth of a yard) which is
f≈650 yds (to nearest whole yard)
But, I wasn't sure, if they just want the diagonal fencing needed then it is just:
f=√28800
f≈170 yds (to nearest yard)
Word form:
Two and seven hundred eighty-nine thousandths
Expanded form:
2
+ 0.7
+ 0.08
+ 0.009