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Vera_Pavlovna [14]
3 years ago
13

Write each answer in Scientific notation 8x10^3 + 6.45 x 10^4

Mathematics
1 answer:
ELEN [110]3 years ago
4 0

Answer:

7.25*10^4 let me know if it is wrong

Step-by-step explanation:

MRK ME BRAINLIEST PLZZZZZZZZZz

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Suppose we are flipping a fair coin (i.e., probability of heads = 0.5 and probability of tails = 0.5). further, suppose we consi
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Here is your answer.

6 0
3 years ago
¼ x 20<br><br> ⅛ x 56<br><br> 0.16 x 32<br><br> 4.5 x 9.1
Kay [80]

Answer:

¼ x 20 = 5

⅛ x 56 = 7

0.16 x 32 = 5.12

4.5 x 9.1 = 40.95

Step-by-step explanation:

7 0
3 years ago
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There are two games involving flipping a coin. In the first game you win a prize if you can throw between 45% and 55% heads. In
Nina [5.8K]

Answer:

d) 300 times for the first game and 30 times for the second

Step-by-step explanation:

We start by noting that the coin is fair and the flip of a coin has a probability of 0.5 of getting heads.

As the coin is flipped more than one time and calculated the proportion, we have to use the <em>sampling distribution of the sampling proportions</em>.

The mean and standard deviation of this sampling distribution is:

\mu_p=p\\\\ \sigma_p=\sqrt{\dfrac{p(1-p)}{N}}

We will perform an analyisis for the first game, where we win the game if the proportion is between 45% and 55%.

The probability of getting a proportion within this interval can be calculated as:

P(0.45

referring the z values to the z-score of the standard normal distirbution.

We can calculate this values of z as:

z_H=\dfrac{p_H-\mu_p}{\sigma_p}=\dfrac{(p_H-p)}{\sqrt{\dfrac{p(1-p)}{N}}}=\sqrt{\dfrac{N}{p(1-p)}}*(p_H-p)>0\\\\\\z_L=\dfrac{p_L-\mu_p}{\sigma_p}=\dfrac{p_L-p}{\sqrt{\dfrac{p(1-p)}{N}}}=\sqrt{\dfrac{N}{p(1-p)}}*(p_L-p)

If we take into account the z values, we notice that the interval increases with the number of trials, and so does the probability of getting a value within this interval.

With this information, our chances of winning increase with the number of trials. We prefer for this game the option of 300 games.

For the second game, we win if we get a proportion over 80%.

The probability of winning is:

P(p>0.8)=P(z>z^*)

The z value is calculated as before:

z^*=\dfrac{p^*-\mu_p}{\sigma_p}=\dfrac{p^*-p}{\sqrt{\dfrac{p(1-p)}{N}}}=\sqrt{\dfrac{N}{p(1-p)}}*(p^*-p)>0

As (p*-p)=0.8-0.5=0.3>0, the value z* increase with the number of trials (N).

If our chances of winnings depend on P(z>z*), they become lower as z* increases.

Then, we can conclude that our chances of winning decrease with the increase of the number of trials.

We prefer the option of 30 trials for this game.

8 0
3 years ago
Find the average rate of change for the given function from x=-1 to x=2.
ICE Princess25 [194]
I would say its A but I'm not 100%
3 0
3 years ago
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These dot plots show the heights (in feet) from a sample of two different types of elephants Asian Elephants . 5 10 11 12 14 15
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Answer:

B - Centers: The Asian elephants have a lower median height than the African elephants

D - Spreads: The heights of the African elephants are more spread out

Step-by-step explanation:

7 0
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