If the sum of 8th and 9th terms of

Mathematics

1 answer:

mojhsa [17]3 years ago

4 0

The answer is anime and chicken nuggets

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A small manufacturing firm has 250 employees. Fifty have been employed for less than 5 years and 125 have been with the company

sukhopar [10]

Answer:

Step-by-step explanation:

Given that a small manufacturing firm has 250 employees. Fifty have been employed for less than 5 years and 125 have been with the company for over 10 years. So remaining 75 are between 5 and 10 years.

Suppose that one employee is selected at random from a list of the employees

A) Probability that the selected employee has been with the firm less than 5 years = $\frac{50}{250 } \\= 0.20$

B) Probability that the selected employee has been with the firm between 5 and 10 years

= $\frac{75}{250 } \\= 0.30$

C) Probability that the selected employee has been with the firm more than 10 years

= $\frac{125}{250} =0.50$

a) P(A) = 0.2

P(C) = 0.5

P(A or B) = 0.2+0.3 = 0.5

P(A and C) = 0 (since A and C are disjoint)

7 0

3 years ago

If t a n squared θ = 3 /8 , what is the value of s e c θ

TEA [102]

We can use 3 facts:

$\tan{\theta}=\frac{y}{x}$

$\sec{\theta}=\frac{r}{x}$

$x^2+y^2=r^2$

So, to find our x and our y we can do:

$\tan^2{\theta}=\frac{3}{8} \implies \\ \tan{\theta}=\pm{\sqrt{\frac{3}{8}}=\pm\frac{\sqrt{3}}{\sqrt{8}}$ So, now that we know our x and our y we can find our r.

$(\sqrt{3})^2+(\sqrt{8})^2=11 \implies r=\sqrt{11}$

You'll notice, though, that there were two solutions for $\tan{\theta}$ , which means we have a positive and a negative for our x. So:

$\sec{\theta}=\frac{\sqrt{11}}{\sqrt{8}} \\ \sec{\theta}=-\frac{\sqrt{11}}{\sqrt{8}}}\\ \text{Rationalizing both of them:}\\ \sec{\theta}=\frac{\sqrt{88}}{8} \\ \sec{\theta}=-\frac{\sqrt{88}}{8}$