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Verdich [7]
1 year ago
15

4. A circle has a radius of 2 cm. a. Find the exact area of the circular region.b Find the approximate area using 3.14 to approx

imate it.
Mathematics
1 answer:
Jobisdone [24]1 year ago
6 0

The formula for the area of circle is,

A=\pi(r)^2

Substitute 2 for r in the formula to obtain the area of circle.

\begin{gathered} A=\pi(2)^2 \\ =12.56637061 \end{gathered}

So, exact area of circle is 1.56637061 square centimeter.

Substitute 2 for r and 3.14 for

\pi

in the formula to obtain the approximate area of circle.

\begin{gathered} A=3.14\cdot(2)^2 \\ =12.56 \end{gathered}

So approximate area of circle is 12.56 square centimeter.

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In order to compare two scales, 30 objects are weighed on both scales. Each object would then have two weight values (one from s
Dominik [7]

Answer:

These two samples are independent samples.

Step-by-step explanation:

Each object would then have two weight values (one from scale 1 and one from scale 2). Based on the nature of the differences in the two weight measurements for the 30 objects, the two scales may be compared.

These two samples are independent samples.

Though the objects are same but the scales are different.

3 0
3 years ago
Type the correct answer in the box.
alexdok [17]

Answer:

250\ cm^3

Step-by-step explanation:

step 1

Find the volume of the prism

The volume of the prism is equal to

V=LWH

we have

L=5\ cm\\W=5\ cm\\H=12\ cm

substitute

V=(5)(5)(12)=300\ cm^3

step 2

Find the volume of the pyramid

The volume of the pyramid is

V=\frac{1}{3}Bh

where

B is the area of the base

B=5^2=25\ cm^2

h=12/2=6\cm ---> half the height of the prism

substitute

V=\frac{1}{3}(25)(6)=50\ cm^3

step 3

we know that

The volume of the space outside the pyramid but inside the prism is equal to subtract the volume of the pyramid from the volume of the cylinder

300\ cm^3-50\ cm^3=250\ cm^3

7 0
4 years ago
Help please!! The measures of the angles of a triangle are shown in the figure below. solve for x
tatiyna

9514 1404 393

Answer:

  x = 33

Step-by-step explanation:

The angles are complementary.

  x° = 90° -57°

  x = 33

3 0
3 years ago
A bathtub contains 45 gallons of water and the total weight of the tub and water is approximately 688.025 pounds. You pull the p
jolli1 [7]

Answer:

a). 8.345v

b). 688.025 - 8.345v

c). 312.5 pounds

d). 21 gallons

Step-by-step explanation:

A bathtub contains amount of water = 45 gallons

And 1 gallon of water weighs = 8.345 pounds

Amount of water drained from the tub since the plug was pulled = v gallons

a) Therefore, weight of v gallons of water drained = 8.345v

b). Since total weight of the tub and water = 688.025 pounds

8.345v pounds of water is drained so total weight of tub and water will be = 688.025 - 8.345v

c). Total weight of the tub when v = 45 or the tub is empty.

Weight of the empty tub = 688.025 - 8.345(45)

= 688.025 - 375.525

= 312.5 pounds

d). If the weight of the tub and water is 487.745 pounds then we have to determine the amount of water drained from the tub.

Let the number gallons of water in the tub is w, then the weight of w gallons water = 8.345w pounds

Weight of the water and tub = weight of water + weight of the tub

487.745 = 8.345w + 312.5

8.345w = 487.745 - 312.5

8.345w = 175.245

w = \frac{175.45}{8.345}

w = 21 gallons

7 0
3 years ago
Draw a line representing the "rise" and a line representing the "run" of the line. State the slope of the line in simplest form.
Paul [167]
The slope is 3/4
you just count how many it goes up before it goes over to a whole unit
8 0
3 years ago
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