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spayn [35]
4 years ago
12

Write an equation of the line passing through the points (−5, 6), (−7, 3)

Mathematics
1 answer:
blsea [12.9K]4 years ago
7 0

Answer:

all work is shown and pictured

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What is the definition of a isosceles triangle
ExtremeBDS [4]
The definition is that an isosceles triangle has two equal sides that are the same degree and the same angle
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3 years ago
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A storage box with a square base must have a volume of 90 cubic centimeters. the top and bottom cost $0.60 per square centimeter
Paul [167]

<u>Answer-</u>

<em>For </em><em>side length of 3.56 cm</em><em> and </em><em>height of 7.10 cm</em><em> the cost will be minimum.</em>

<u>Solution-</u>

Let us assume that,

x represents the length of the sides of the square base,

y represent the height.

Given the volume of the box is 90 cm³, so

\Rightarrow V=90\\\\\Rightarrow x^2\times y=90\\\\\Rightarrow y=\dfrac{90}{x^2}

As the top and bottom cost $0.60 per cm² and the sides cost $0.30 per cm². Total cost C will be,

C=\text{cost for top and bottom}+\text{cost for rest 4 sides}\\\\=(2x^2\times 0.6)+(4xy\times 0.3)\\\\=(2x^2\times 0.6)+(4x\times \frac{90}{x^2}\times 0.3)\\\\=1.2x^2+ \dfrac{108}{x}

Then,

C'=\dfrac{d}{dx}(1.2x^2+ \dfrac{108}{x})=2.4x-\dfrac{108}\\\\C''=\dfrac{d^2}{dx^2}(1.2x^2+ \dfrac{108}{x})=2.4+\dfrac{216}{x^3}

As C'' has all positive terms  so, for every positive value of x (as length can't be negative), C'' is positive.

So, for minima C' = 0

\Rightarrow 2.4x-\dfrac{108}{x^2}=0\\\\\Rightarrow 2.4x=\dfrac{108}{x^2}\\\\\Rightarrow x^3=\dfrac{108}{2.4}=45\\\\\Rightarrow x=3.56

Then,

y=\dfrac{90}{x^2}

y=\dfrac{90}{3.56^2}

y=7.10

Therefore, for side length of 3.56 cm and height of 7.10 cm the cost will be minimum.

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Is there a way to do this or is it a mistake (10c please)<br><br> Given g(x) = -x^2+9, find f(0)
Olenka [21]

Answer:f(0)=9

Step-by-step explanation:

g(0)=(-0)^2+9

g(0)=0+9

g(0)=9

4 0
3 years ago
Consider the function f(x)= (x+4)(x-2) what is the equation of the axis of symmetry
almond37 [142]

if we zero out f(x), namely make y = 0, we can get the roots or x-intercepts for this quadratic equation

\bf 0 = (x+4)(x-2)\implies \begin{cases} 0=x+4\implies &-4=x\\ 0=x-2\implies &2=x \end{cases}

now, the equation is in x-terms, meaning is a vertically opening parabola, so the axis of symmetry will be x = something, a vertical line.

well, we have two x-intercepts, one at -4 and another at 2, and the vertex is right half-way between those guys

-4------------(-1)------------2

so the vertex is at x=-1, namely the axis of symmetry is x = -1.

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15 computers for 45 students, 45 computers for 135 students
dusya [7]
15 x 45 = 675
45 x 135 =6075
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3 years ago
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