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1 year ago

What is the perimeter of the triangle (4,1) (2,5) (1,-1)

Mathematics

1 answer:

Naya [18.7K]1 year ago

3 0

the perimeter of the triangle=14.38

The coordinates of the triangle (4,1),(2,5),(1,-1);

In geometry, the perimeter of a shape is defined as the total length of its boundary.

The perimeter of the triangle is the sum of all the sides of the triangle =a+b+c (assuming a,b, and c are the sides of the triangle)

By using the distances formula find the length of the sides of the triangle:√[(x₂ - x₁)² + (y₂ - y₁)²],

where (x₁,y₁),(x₂,y₂) are the coordinates ,

a=√[(4 - 2)² + (1- 5)²] = $\sqrt 20$ =4.7

b=√[(2 -1)² + (5 -(-1))²]= $\sqrt37$ =6.08

c=√[(1 -4)² + ((-1)-1)²]= $\sqrt13$ =3.60

the perimeter of the triangle=a+b+c=4.7+6.08+3.60=14.38

hence ,perimeter of the triangle=14.38

Learn more about perimeter of triangle:

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Suppose a certain computer virus can enter a system through an email or through a webpage. There is a 40% chance of receiving th

DedPeter [7]

Answer:

P = 0.42

Step-by-step explanation:

This probability problem can be solved by building a Venn like diagram for each probability.

I say that we have two sets:

-Set A, that is the probability of receiving this virus through the email.

-Set B, that is the probability of receiving it through the webpage.

The most important information in these kind of problems is the intersection. That is, that he virus enters the system simultaneously by both email and webpage with a probability of 0.17. It means that $A \cap B$ = 0.17.

By email only

The problem states that there is a 40 chance of receiving it through the email. It means that we have the following equation:

$A + (A \cap B) = 0.40$

$A + 0.17 = 0.40$

$A = 0.23$

where A is the probability that the system receives the virus just through the email.

The problem states that there is a 40% chance of receiving it through the email. 23% just through email and 17% by both the email and the webpage.

By webpage only

There is a 35% chance of receiving it through the webpage. With this information, we have the following equation:

$B + (A \cap B) = 0.35$

$B + 0.17 = 0.35$

$B = 0.18$

where B is the probability that the system receives the virus just through the webpage.

The problem states that there is a 35% chance of receiving it through the webpage. 18% just through the webpage and 17% by both the email and the webpage.

What is the probability that the virus does not enter the system at all?

So, we have the following probabilities.

- The virus does not enter the system: P

- The virus enters the system just by email: 23% = 0.23

- The virus enters the system just by webpage: 18% = 0.18

- The virus enters the system both by email and by the webpage: 17% = 0.17.

The sum of the probabilities is 100% = 1. So:

P + 0.23 + 0.18 + 0.17 = 1

P = 1 - 0.58

P = 0.42

There is a probability of 42% that the virus does not enter the system at all.

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