Given that o<span>ne Friday night,
Roman and Malou are busy studying for their Logic exam. Meanwhile,
Hadji just tweeted a picture of himself eating crispy pata and sisig.
Jeff is sound asleep in his dorm room.
Part A:
The truth value of </span>"Either Roman has a date with Malou, or Jeff is sleeping or Hadji is eating." is obtained as follows:
From the scenario, the truth value of the individual statements are as follows:
<span>Roman has a date with Malou is True
</span>
<span>Jeff is sleeping is True
</span>
<span>Hadji is eating is True
Thus, the truth value of "True" or "True" or "True" is True.
Therefore, the truth value of "</span><span>Either Roman has a date with Malou, or Jeff is sleeping or Hadji is eating." is True.
Part B:
</span>The truth value of "Either Jeff is sleeping or Hadji is not eating" is obtained as follows:
From the scenario, the truth value of the individual statements are as follows:
<span>Jeff is sleeping is True
</span>
<span>Hadji is not eating is False
Thus, the truth value of "True" or "False" is True.</span>
Therefore, the truth value of "Either Jeff is sleeping or Hadji is not eating" is True.
Part C:
The truth value of "Roman and Malou are on a date and Jeff is sleeping, or Hadji is not eating." is obtained as follows:
From the scenario, the truth value of the individual statements are as follows:
Roman and Malou are on a date is True
<span>Jeff is sleeping is True
</span>
<span>Hadji is not eating is False
The truth value of "True" and "True" is True.
The truth value of "True" or "False" is True.
Thus, the truth value of ("True" and "True") or "False" is True.
</span>
Therefore, the truth value of "Roman and Malou are on a date and Jeff is sleeping, or Hadji is not eating." is True.
Answer:
300
Step-by-step explanation:
Answer:
<em>total</em><em>=</em><em>n÷m</em><em> </em><em>$</em><em>1</em><em>6</em><em>5</em><em>÷</em><em>1</em><em>5</em><em>,</em><em>$</em><em>2</em><em>3</em><em>1</em><em>÷</em><em>2</em><em>1</em><em> </em><em>and</em><em> </em><em>$</em><em>2</em><em>7</em><em>5</em><em>÷</em><em>2</em><em>5</em>
Answer:
175/3 or 58.333...
Step-by-step explanation:
This is fairly complicated but I will try to make it as simple as possible. I also apologize in advance for how impossible it is to make fractions look like fractions. I also had to insert a bunch of unnecessary parentheses just because the fractions that I can make are relatively inaccurate.
The distance between 2 cities can be represented as d.
Time is d/r if r is rate, so B->NY=d/50
Similarly,NY->B is d/70
Obviously the average speed is 2d/(d/50+d/70), this is just an average time
Now just remove the d and get (d/d)*2/(1/50+1/70)
You can now multiply by the LCM/LCM, which is 350/350.
After calculating you will get 700/12 which is 58.333...(This is how to enter into your RSM browser) Hope this helps. Sorry it is so late.
Answer: x=68/11 and y=-72/11
Steps:
2(x+4y=-20)
2x+8y=-40
2x - 3y = 32
- 2x + 8y = -40
-11y=72
y=-72/11
x + 4(-72/11) = -20
x - 288/11 = -20
x=68/11