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Mathematics

1 answer:

il63 [147K]2 years ago

4 0

Answer:

I'm not completely sure, but I think the correct answer is option D.

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Find the formula an for the nth term of the geometric sequence satisfying the following conditions: a1 = -2,

Alexeev081 [22]

Answer:

Step-by-step explanation:

a1 = - 2

an = a1 * r^(n - 1)

a6 = -486

-486 = - 2 * r^(6-1) Divide by 2

243 = r^5

The largest value that r could be is 3.

4^5 = 1024

(243)^(1/5) = 3

So the general formula

an = -2*(3)^(n - 1)

3 0

2 years ago

Please Help Me <br> Thank u so much

BartSMP [9]

The location of the vertex tells you the horizontal and vertical shift. (The parent function f(x) = x² has its vertex at the origin, (0, 0). The vertical distance of the point 1 unit left or right of the vertex in relation to the vertex tells you the vertical scale factor (stretch).

g(x) = f(x +3) -3
horizontal shift left 3
vertical shift down 3

h(x) = -3f(x)
reflection across the x-axis
vertical stretch of 3

d(x) = f(x -3) -3
horizontal shift right 3
vertical shift down 3

6 0

3 years ago

2v^2-12 =-12v <br> Would really appreciate it loves❤️

Black_prince [1.1K]

For this case we have the following equation:

$2v ^ 2-12 = -12v$

Rewriting we have:

$2v ^ 2 + 12v-12 = 0$

Dividing by 2 to both sides of the equation:

$v ^ 2 + 6v-6 = 0$

We apply the quadratic formula:

$x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2a}$

We have to:

$a = 1\\b = 6\\c = -6$

Substituting:

$x = \frac {-6 \pm \sqrt {6 ^ 2-4 (1) (- 6)}} {2 (1)}\\x = \frac {-6 \pm \sqrt {36 + 24}} {2}\\x = \frac {-6 \pm \sqrt {60}} {2}\\x = \frac {-6 \pm \sqrt {4 * 15}} {2}\\x = \frac {-6 \pm2 \sqrt {15}} {2}$