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qaws [65]
8 months ago
13

Place the following events of muscle excitation in the correct order.

Biology
1 answer:
svetlana [45]8 months ago
7 0

An motion potential in the presynaptic cell activates calcium channels. Ca+ triggers the discharge of Acetylcholine through exocytosis. Ach binds its receptors in the postsynaptic membrane, opening Na+ channels. The Order is 4, 3, 5, 1, 2.

The principal frightened system generates an motion potential that travels to the goal activating the calcium channels ⇒ event (4)

Calcium triggers vesicles fusion to the presynaptic membrane. By exocytosis, vesicles release the neurotransmitter -Acetylcholine- into the synaptic space ⇒ event (3)

Once there, Ach binds to its receptors on the postsynaptic membrane of the skeletal muscle fiber, causing ion channels to open ⇒ event (5)

Positively charged sodium ions move the membrane to get into the muscle fiber (sarcoplasm) and potassium leaves the cell ⇒ event (1)

The distinction in charges, resulting from these ions' transport, positively charges the fiber membrane. The postsynaptic cell depolarizes ⇒ Event (2)

The motion potential enters the t-tubules depolarizing the internal part of the muscle fiber. Contraction initiates while the motion potential depolarizes the internal part of the muscle fiber. Calcium channels spark off in the T tubules membrane, releasing calcium into the sarcolemma.

At this point, the muscle is at rest, and the tropomyosin is inhibiting the appeal strengths between myosin and actin filaments. Tropomyosin is obstructing binding sites for myosin on the skinny filament.

When calcium enters the sarcolemma, it binds to troponin C, and troponin T alters the tropomyosin role through shifting it and unblocking the binding sites.

Myosin heads be a part of the uncovered actin-binding points forming move-bridges, and whilst doing so, ATP turns into ADP and inorganic phosphate, that's released.

Myofilaments slide impulsed through chemical energy accumulated in myosin heads, generating a strength stroke. The strength stroke initiates while the myosin move-bridge binds to actin. As they slide, ADP molecules are released. A new ATP hyperlinks to myosin heads and breaks the bindings to the actin filament.

Then ATP splits into ADP and phosphate, and the energy produced is gathered in the myosin heads, which begins offevolved a new binding cycle to actin.

Finally, Z-bands are pulled towards every other, and the sarcomere and the I-band get shorter, generating muscle fiber contraction.

According to those steps, the appropriate order of activities is 4, 3, 5, 1, 2.

To learn more about Acetylcholine, click here:

brainly.com/question/13821381

#SPJ4

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[Chapter 3-4] A cross was carried out between the following two pureline parental strains:Parent 1: A/A; b/b; D/D; e/e; F/FParen
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Following the selfing of the F1 from the cross between the two parental strains, what proportion of the F2 individuals will phenotypically resemble either one of the two parental lines?

= 7.03% of F2 progeny will resemble parent 1

= 2.34% of F2 progeny will resemble parent 2.

Explanation:

Parent 1: AA; b/b; D/D; e/e; F/F

Parent 2: a/a; B/B; d/d; E/E; f/f

F1 Progeny: A/a; B/b; D/d; E/e; F/f

knowing that the F1 progeny is selfed, the possible gamete outcomes are:

ABDeF , ABDEf, ABdeF, ABdEf

AbDeF , AbDEf , AbdeF , AbdEf

aBDeF , aBDEf , aBdeF , aBdEf

abDeF , abDEf , abdeF , abdEf

All gametes are either eF or Ef (the two parental genotypes) and never EF or ef.

At the A, B and D loci, the F1 are heterozygotes. Therefore, in the F2 progeny, for each locus, 3/4 of the progeny will have the dominant trait while 1/4 will have the recessive phenotype. Further, 1/2 of all F2 progeny will have the haplotype eF and the other half will be Ef.

<u>Proportion of progeny resembling Parent 1: </u>

Parent 1 has the Phenoytpe AbDeF. As previously discussed, 3/4th of all F2 progeny has the phenotype A, 1/4th of F2 progeny has the phenotype b, 3/4th of F2 progeny has the phenotype D and 1/2 of F progeny has the phenotype eF.

Thus, the proportion of progeny resembling Parent 1

= 3/4 x 1/4 x 3/4 x 1/2 = 0.0703125

= 7.03% of F2 progeny will resemble parent 1.

<u>Proportion of progeny resembling Parent 2</u>:

Parent 2 has the Phenoytpe aBdEf. As previously discussed, 1/4th of all F2 progeny has the phenotype a, 3/4th of F2 progeny has the phenotype B, 1/4th of F2 progeny has the phenotype d and 1/2 of F progeny has the phenotype Ef.

Thus, Proportion of progeny resembling parent 2

= 1/4 x 3/4 x 1/4 x 1/2 = 0.0234375

= 2.34% of F2 progeny will resemble parent 2.

7 0
2 years ago
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