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Sedaia [141]
1 year ago
11

You are playing a card game where the total points you earn depends on theasuits of the cards you draw. The total number of poin

ts is given by the expression3a + 3b-2c-2d, where a represents the number of hearts, b is diamonds, c isclubs, and d is spades. What is the total number of points you earn if you draw 3hearts, 2 diamonds and 1 spade? *
Mathematics
1 answer:
Semmy [17]1 year ago
4 0

3a + 3b-2c-2d

a= number of hearts

b= number of diamons

c= number of clubs

d= number of spades

if you draw 3hearts, 2 diamonds, and 1 spade, just replace a=3, b=2, c=0, d=1

3(3) + 3(2)-2(0)-2(1)

Multiply each term and add the results:

9+6-0-2 = 13

13 points

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3 years ago
The expression 2x+50 represents the elevation above sea level, in meters, of a rock climber after x minutes of climbing. What is
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3 years ago
Determine the reactions at the supports of the beam which is loaded as shown.
Mazyrski [523]

As shown... where? I have no idea what you are talking about or referencing to.

4 0
4 years ago
4x+8=2(2x+4)<br><br> a. infinite solutions<br> b. one solution<br> c. no solution
kramer

Answer:

4x+8 = 4x + 8

0=0

the answer is a

8 0
4 years ago
Read 2 more answers
Which of the following is equivalent to tan2θcos(2θ) for all values of θ for which tan2θcos(2θ) is defined?
Aloiza [94]

Answer:

2sin²θ - tan²θ

Step-by-step explanation:

Given

tan²θcos(2θ)

Required

Simplify

We start by simplifying cos(2θ)

cos(2θ) = cos(θ+θ)

From Cosine formula

cos(A+A) = cosAcosA - sinAsinA

cos(A+A) = cos²A - sin²A

By comparison

cos(2θ) = cos(θ+θ)

cos(2θ) = cos²θ - sin²θ ----- equation 1

Recall that cos²θ + sin²θ = 1

Make sin²θ the subject of formula

sin²θ = 1 - cos²θ

Substitute sin²θ = 1 - cos²θ in equation 1

cos(2θ) = cos²θ - (1 - cos²θ)

cos(2θ) = cos²θ - 1 +cos²θ

cos(2θ) = cos²θ + cos²θ - 1

cos(2θ) = 2cos²θ - 1

Substitute 2cos²θ - 1 for cos(2θ) in the given question

tan²θcos(2θ) becomes

tan²θ(2cos²θ - 1)

Open brackets

2cos²θtan²θ - tan²θ

------------------------

Simplify tan²θ

tan²θ = (tanθ)²

Recall that tanθ =  sinθ/cosθ

So, we have

tan²θ = (sinθ/cosθ)²

tan²θ = sin²θ/cos²θ

------------------------

Substitute sin²θ/cos²θ for tan²θ

2cos²θtan²θ - tan²θ becomes

2cos²θ(sin²θ/cos²θ) - tan²θ

Open bracket (cos²θ will cancel out cos²θ) to give

2(sin²θ) - tan²θ

2sin²θ - tan²θ

Hence, the simplification of tan²θcos(2θ) is 2sin²θ - tan²θ

Option E is correct

7 0
3 years ago
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