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tiny-mole [99]
3 years ago
9

You are hanging 3 display shelves with the same width on a wall so that there is 18 inches of space above each shelf for placing

items.Each shelf is 3 inches wide. You want the space from the ceiling to the top 18 inches of space and the space below the bottom shelf to a chair rail to be the same. Determine the distance from the ceiling to the bottom of each of the shelves so that you can install them. Explain how you got your answer.
Mathematics
1 answer:
Kazeer [188]3 years ago
4 0

Answer:

You need to have a minimum of 16 inches of clearance.

Step-by-step explanation:

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How many days in one week?​
Tcecarenko [31]

Answer:

7 , Monday, Tuesday, Wednesday, Thursday, Friday, then you have you r weekend Saturday, Sunday, then you restart the week . :)

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Can some one help me asap
zavuch27 [327]
It'd be easier to do #18 if y ou were to break it up:

                                                        14* (first term + 14th term)
Sum from n=1 to 14 of n =  S      = ---------------------------------
                                               14                       2
                                    
     14(1+14)
= ---------------- = 7(15) = 105 
           2

The sum of twice that is 210.  The sum of "1 from n=1 to n=14" is just 14.

The final sum is 210 + 14 = 224 (answer)
4 0
3 years ago
WUHAHAHAHHAHAH HELP ME<br><br><br><br>​
Nat2105 [25]

Answer:

1. 201.06 m

2. 1963.5 dm

3. 4536.46 mm

4. 17671.46 in

5. 254.47 cm

Step-by-step explanation:

You just have to plug these numbers into the formula for area of a circle.

6 0
3 years ago
Please help me <br><br>If 180°&lt;α&lt;270°, cos⁡ α=−8/17, what is sin -α?
rewona [7]

Starting from the fundamental trigonometric equation, we have

\cos^2(\alpha)+\sin^2(\alpha)=1 \iff \sin(\alpha)=\pm\sqrt{1-\cos^2(\alpha)}

Since 180, we know that the angle lies in the third quadrant, where both sine and cosine are negative. So, in this specific case, we have

\sin(\alpha)=-\sqrt{1-\cos^2(\alpha)}

Plugging the numbers, we have

\sin(\alpha)=-\sqrt{1-\dfrac{64}{289}}=-\sqrt{\dfrac{225}{289}}=-\dfrac{15}{17}

Now, just recall that

\sin(-\alpha)=-\sin(\alpha)

to deduce

\sin(-\alpha)=-\sin(\alpha)=-\left(-\dfrac{15}{17}\right)=\dfrac{15}{17}

6 0
3 years ago
Read 2 more answers
12. In the given figure, RS is parallel to PQ, If RS = 3 cm, PQ = 6 cm and ar(∆TRS) = 15cm³, then ar (∆TPQ) = ? (a) 70 cm² (b) 5
Gnesinka [82]

\large\underline{\sf{Solution-}}

Given that,

In <u>triangle TPQ, </u>

  • RS || PQ,

  • RS = 3 cm,

  • PQ = 6 cm,

  • ar(∆ TRS) = 15 sq. cm

As it is given that, <u>RS || PQ</u>

So, it means

⇛∠TRS = ∠TPQ [ Corresponding angles ]

⇛ ∠TSR = ∠TPQ [ Corresponding angles ]

\rm\implies \: \triangle TPQ \:  \sim \: \triangle TRS \:  \:  \:  \:  \:  \:  \{AA \}

<u>Now, We know </u>

Area Ratio Theorem,

This theorem states that :- The ratio of the area of two similar triangles is equal to the ratio of the squares of corresponding sides.

\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{ar( \triangle \: TRS)}  = \dfrac{ {PQ}^{2} }{ {RS}^{2} }

\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{15}  = \dfrac{ {6}^{2} }{ {3}^{2} }

\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{15}  = \dfrac{36 }{9}

\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{15}  = 4

\rm\implies \:ar( \triangle \: TPQ)  = 60 \:  {cm}^{2}

3 0
2 years ago
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