Question

consider the right triangle inside the circle with a center at point E(1,1). which equation can be used to show how he pythagorean theorem can lead to an equation for the circle?

Answer 1

The standard form of a circle is:

$(x-h)^2+(y-k)^2=r^2$

Where

(h, k) is the center

r is the radius

Since the center is (1, 1), we can write:

$(x-1)^2+(y-1)^2=r^2$

EG (hypotenuse of the right triangle) is the radius of the circle. Thus, we can say >>>

$(x-1)^2+(y-1)^2=(LengthOfEG)^2$

The correct answer is

B