(x - 1)2 - 4(X + 1) + 2 = 0
2x - 2 - 4x - 4 + 2 = 0
(2x - 4x) - 4 = 0
-2x = 4
x = 4/-2
x = -2
Answer:
c ≈ 6.08 m
Step-by-step explanation:
Your question is how to solve for a missing side length of a triangle when given 2 sides length and an angle. The side length can be solved using the cosine rule . We use cosine rule to find the length of a side of a triangle when given two sides and an included angle.
The cosine rule formula for finding a side length are as follows
c² = a² + b² - 2ab cosC
b² = a² + c² - 2ac cosB
c² = a² + b² - 2ab cosC
Using cosine rule
c² = 4² + 3² - 2 × 4 × 3 cos 120°
c² = 16 + 9 - 24 cos 120°
c² = 25 - 24 (-0.5)
c² = 25 + 12
c² = 37
square root both sides
c = √37
c = 6.0827625303
c ≈ 6.08 m
Answer:
Its C because each % is not one student
Step-by-step explanation:
Answer:
cosjk = √55 i/3
tanjk = 8/√55 i
Step-by-step explanation:
Given
sin jk = 8/3
According to SOH CAH TOA
Sin theta = opposite/hypotenuse = 8/3
Opposite = 8
hypotenuse = 3
Get the adjacent using the pythagoras theorem
hyp² = opp²+adj²
adj² = hyp² - opp²
adj² = 3² - 8²
adj² = 9-64
adj² = -55
adj = √-55
adj = √55 i (i = √-1)
Get cosjk
cosjk = adj/hyp
cosjk = √55 i/3
Get tanjk
tanjk = opp/adj
tanjk = 8/√55 i
So the first one is -0.5 and second is -0.5 the third one is -0.5 and the fourth is -0.25 so I would say that is D
