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Damm [24]
3 years ago
6

Can someone pls help me with this?!

Mathematics
1 answer:
Vilka [71]3 years ago
8 0

Answer:

1188

Step-by-step explanation:

33 X 36 = 1188

TO FIND AREA: Height x width= area

Height is 33 Width is 36

40 is just a distraction! :)

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The rate of inflation is 3%. The cost of an item in future years can be found by iterating the function c(x)=1.03x. Find the cos
emmainna [20.7K]

year 1

cost = 1.03 (1500) = 1545

put 1545 in for x in year 2

year 2

1.03 * 1545 = 1591.35

put in 1591.35 in for x in year 3

year 3

1.03 *1591.35=1639.0905

round to the nearest cent

cost  in three years: $1639.09

Choice C

6 0
3 years ago
Carrie has 40 more nickels than Joan has dimes. They both have the same amount of money. How many coins does each girl have? Wha
LuckyWell [14K]

Answer:

Carrie and Joan have 80 nickels and 40 dimes, respectively, and each one has an amount of money of 4 US dollars.

Step-by-step explanation:

Let be x and y the amounts of nickels and dimes that Carrie and Joan have, as c the total amount of money that both Carrie and Joan have. A nickel is a five cent coin and a dime is a ten cent coin.

The following equations are constructed after a careful reading on statement:

Carrie's amount of money:

0.05\cdot x = c (Eq. 1)

Joan's amount of money:

0.10\cdot y = c (Eq. 2)

Relation between amounts of coins:

x = y+40 (Eq. 3)

First we eliminate c by equalizing (Eq. 1) and (Eq. 2):

0.05\cdot x = 0.10\cdot y

Then, we reduce the resulting formula by (Eq. 3):

0.05\cdot (y+40) = 0.10\cdot y

y+40 = 2\cdot y

y = 40

And rest of variable are now determined:

x = 40+40

x = 80

c = 0.05\cdot (80)

c  = 4

Carrie and Joan have 80 nickels and 40 dimes, respectively, and each one has an amount of money of 4 US dollars.

5 0
3 years ago
What is the answer to this question?
Vladimir [108]
The answer is A. Hope this helped
7 0
3 years ago
A 6,000​-seat theater has tickets for sale at ​$28 and ​$40. How many tickets should be sold at each price for a sellout perform
RUDIKE [14]

Answer:

2,100 $28 tickets were sold, and 3,900 $40 tickets were sold!

Step-by-step explanation:

So, we need to write two equations in order to solve this:

We will think of 28 dollar tickets as x, 40 dollar tickets as y.

Now lets make those equations:

x + y = 6,000

             and

28x+40y = 193,200

Now, to solve for x and y, lets set a value for x or y. In this case I will set the value of y:

I will do this by taking x + y = 6,000, and subtracting x to the other side, to get y alone:

y = 6,000 - x

Now lets plug in y to our second equation:

28x + 40(6,000-x) = 193,2000

=

28x+240,000-40x = 193,200

Now combining like terms and solving for x we get:

-12x + 240,000 = 193,200

=

-12x = -46,800

=

x=3,900

Now that we know x, lets solve for y by plugging into our first equation!

3,900 + y = 6,000

=

y = 2,100

So now we know that our answer is:

2,100 $28 tickets were sold, and 3,900 $40 tickets were sold!

Hope this helps! :3

7 0
2 years ago
Solve for x: u = k + yx
zhannawk [14.2K]
X
=
u
y
−
k
y
is the answer
x= u/y - k/y
4 0
3 years ago
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