Dimensions are length 20 meter and width 14 meter
<em><u>Solution:</u></em>
Let "a" be the length of rectangle
Let "b" be the width of rectangle
Given that,
<em><u>A rectangle has width that is 6 meters less than the length</u></em>
Width = length - 6
b = a - 6
The area of the rectangle is 280 square meters
<em><u>The area of the rectangle is given by formula:</u></em>

<em><u>Substituting the values we get,</u></em>

<em><u>Solve the above equation by quadratic formula</u></em>



Since, length cannot be negative, ignore a = -14
<em><u>Thus solution of length is a = 20</u></em>
Therefore,
width = length - 6
width = 20 - 6 = 14
Thus dimensions are length 20 meter and width 14 meter
Assuming LCD means Lowest Common Denominator
Assuming by "and" you mean adding the two
Well, you go by the multiples of 7;
7, 14, 21, 28, 35, 42, 49, 56, 63,<u> 70</u>
Multiples of 10;
10, 20, 30, 40, 50, 60, <u>70</u>, 80, 90, 100
Straight away you can see the lowest common multiple is 70,
Now to go about adding them,
2/7 * 10 (both sides) , 20/70
9/10 * 7 (both sides) , 63/70
Then you add the two; 20/70 + 63/70 - now we can add them because they share the same denominator
20/70 + 63/70 = 83/70 = 1 whole 13/70 (simplified)
<u>The LCD is 70
Quick tip, </u>to find a common multiple (not necessarily the lowest) multiply the two denominators.
Answer:
Step-by-step explanation:
7.3
It should be 153! Hopefully that helps
Answer:
C. 180-degree rotation counterclockwise followed by a translation of 5 units to the left
Step-by-step explanation: