Which of the following relations has a domain of {2, 3, 6}? Choose all that apply. {(3, 3), (2, 2), (3, 2), (6, 1)} {(3, 1), (6,
Ganezh [65]
All except (0,2), (5,6), (5,3), and (4,3). The domain is the x and the range is the y, so the x coordinate has to either be 2, 3, or 6.
A.
= (x + 2)^2 - 4 - 11
= (x + 2)^2 - 15
B. vertex is at ( -2, -15) which is a minimum because the coefficient of x^2 is positive.
C. The axis of symmetry is a vertical line passing through the vertex It is
x = -2.
Unsecured credit cards could possibly be the answer
Lets start by factoring the 216 into its smaller parts.
![\sqrt[3]{2 * 2 * 2 * 3 * 3 * 3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B2%20%2A%202%20%2A%202%20%2A%203%20%2A%203%20%2A%203%7D)
From here, we can separate the three 2s and the three 3s into two separate radicals.
![\sqrt[3]{2*2*2} * \sqrt[3]{3*3*3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B2%2A2%2A2%7D%20%2A%20%20%5Csqrt%5B3%5D%7B3%2A3%2A3%7D%20)
Since we have three copies of the same number in each, the answer to the cube root is the number we have the copies of.
![\sqrt[3]{2*2*2} * \sqrt[3]{3*3*3} = 2 * 3](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B2%2A2%2A2%7D%20%2A%20%20%5Csqrt%5B3%5D%7B3%2A3%2A3%7D%20%3D%202%20%2A%203)
Finally, we just need to multiply out what remains to find the solution.

So, the final answer is 6.