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Mila [183]
3 years ago
6

Simplify your answer and write it as a proper fraction or as a whole or mixed number.6 2/11 1/11 =

Mathematics
1 answer:
Kisachek [45]3 years ago
4 0
6 3/11=6 2/11 + 1/11 = 6 3/11
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Diving simply the following: 3 power 12÷3 power 7​
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Can someone help with this please
nasty-shy [4]

Answer:

22x^2 -10xy + 12x

Step-by-step explanation:

To add and subtract polynomials, combine only like terms. When doing it vertically, stack polynomials and line up the same bases and exponents. Once this is done, simply add and subtract the coefficients.

  10x^2 + 12xy + 4x

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22x^2 -10xy + 12x

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A wholesaler requires a minimum of 4 items in each order from its retail customers. The manager of one retail store is consideri
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Answer:

  • It is the last graph: solid line, shaded area over the line x = 2 - x/2

Explanation:

1) <u>Set the algebraigic expression that represents the combinations of sofa and pillow orders:</u>

  • Number of sofas: x (given)
  • Number of pillows: 2y (given, since they come in pairs)
  • Number of items = number of sofas + number of pillows = x + 2y
  • Minimum of 4 items in each order (given) ⇒ x + 2y ≥ 4

<u>2) Predict the graph of the inequality x + 2y ≥ 4</u>

  • The border line is the equation x + 2y = 4
  • You can choose two points to draw a line
  • Choose the axis-intercepst:

        x = 0 ⇒ 2y = 4 ⇒ y =4/2 ⇒ y = 2 ⇒ point (0,2)

        y = 0 ⇒ x = 4 ⇒ point (4,0)

        Then the lines goes through (0,2) and (4,0) ... [the four graphs meet this]

  • The shading area is above the line because when you solve for y you get y ≥   2 - x/2, and the line is included because the "equal to" part of the symbol (≥ means greater than or equal to).

  •  To state that the line is included the graph uses a continous line instead of a dotted one.

<u>3) Conclusion:</u>

That means that the correct graph is the last one: solid line, shaded area over the line y = 2 - x/2.

Note: a more detailed graph would include the fact that the items cannot be negative, i.e. x ≥ 0 and y ≥ 0, which would result in that the shaded area would be on the first quadrant.

   

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