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Artist 52 [7]
1 year ago
3

Ben start walking along a path at 2 mi/h. one and a half hours after ben leaves, his sister jen begins to jogging along the same

path at 7mi/h. how long (in hours) will it be before jen catches up to ben.
Mathematics
1 answer:
Tanzania [10]1 year ago
8 0

Answer:

Let t be the time traveled by Ben

2 mph * t = S        where S is the distance traveled

7 mph * (t - 1.5) = S       same distance as Ben

2 t = 7 t - 10.5

5 t = 10.5    

t = 2.1          where t is in hours

So Ben travels for 2.1 hrs

Jen travels for 2.1 - 1.5 = .6 hrs before catching Ben

Check:

2 * 126 min = 7 * 36 min

252 = 252

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