Ben start walking along a path at 2 mi/h. one and a half hours after ben leaves, his sister jen begins to jogging along the same
path at 7mi/h. how long (in hours) will it be before jen catches up to ben.
1 answer:
Answer:
Let t be the time traveled by Ben
2 mph * t = S where S is the distance traveled
7 mph * (t - 1.5) = S same distance as Ben
2 t = 7 t - 10.5
5 t = 10.5
t = 2.1 where t is in hours
So Ben travels for 2.1 hrs
Jen travels for 2.1 - 1.5 = .6 hrs before catching Ben
Check:
2 * 126 min = 7 * 36 min
252 = 252
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