So the perimeter(P) of a rectangle would be:
P= 2L+2W
L being the length and W being the width.
The problem says the length is 4cm more than the width, so L= 4+W.
So if we substitute L with 4+W, we get:
P= 2(4+W) + 2W
Use the Distributive Property
P= 8+2W+2W
Combine like terms
P=8+4W
Since we're given the perimeter, we could replace P with 52. So:
52=8+4W
Subtract 8 to both sides
44=4W
Divide 4 to both sides
11=W
Therefore, the width is 11cm
And since the length is 4cm more than the width, we could add 4cm to 11cm to find that the length is 15cm
Thus, the dimensions of the rectangle are 15cm by 11cm
So the equation is x + 2x + 5= 29
Here are the steps -5 -5
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3x = 24
Divide both sides by 3 so you get
x = 8
Then look back at the question, the second number has to be twice that number plus 5
So the 1st number is 8 The second # is 2(8)+5= 21
Answer:
Two more cm. ALl you need to do now is convert it to cubic cm because I do not know how to do that.
Step-by-step explanation:
Y > 6x + 5
y < -6x + 7
(2,17)
17 > 6(2)+5 ; 17> 17 NO
(8,8)
8>6(8)+5 NO
(-2,18)
18>6(-2)+5
18>-7 YES
18< -6(-2)+7
18< 12+7 YES (-2,18) is an answer
(0,6)
6>6(0)+5
6>5 YES
6<-6(0)+7
6<7 YES (0,6) is an answer
(-2,19)
19>6(-2)+5
19>-7 NO
(2,18)
18>6(2)+5
18>17 YES
18< -6(2)+7
18< -5 NO
