Now move vertices A, B, and C of ∆ABC to create a triangle of your choice. (Note: the tool will allow you to create only certain
2 answers:
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Answer:
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Explanation:
The symbol is the greek letter theta. It's often used in trigonometry for angles.
In this case,
So,
You'll need to use a reference sheet or the unit circle to determine the value of cos(30). Or you could use a 30-60-90 triangle template.
When using the unit circle, look in the upper right quadrant (which is quadrant 1). The angle 30 degrees is in this quadrant. Locate the terminal point and note how is the x coordinate of the terminal point. This is due to
Side note:
<h2>Answer:</h2>
angle QRS = 51°
<h2>Step-by-step explanation:</h2>
The diagram for the question has been attached to this response.
From the diagram, some circle theorems can be applied.
<em><u>Circle theorem:</u></em>
The angle subtended by an arc of a circle at the centre is twice the angle subtended by it at any other point on the remaining part of the circle.
From the diagram, QR is the arc and therefore:
∠QSR = 2 x ∠ QTR
<em>Since ∠QTR = 39°</em>
=> ∠QSR = 2 x 39°
=> ∠QSR = 78°
<u><em>Other theorem:</em></u>
(i)The base angles of an isosceles triangle are equal.
Triangle QSR is an isosceles triangle, therefore, angles SQR and QRS are equal. i.e
∠SQR = ∠QRS
(ii) The sum of angles of a triangle is 180°. i.e
∠SQR + ∠QRS + ∠QSR = 180°
<em>Since ∠SQR = ∠QRS and ∠QSR = 78°</em>
=> ∠QRS + ∠QRS + 78° = 180°
=> 2(∠QRS) = 180° - 78°
=> 2(∠QRS) = 102°
<em>Divide both sides by 2</em>
=> ∠QRS = 51°
Therefore, angle QRS = 51°