Answer:
The total number of apples is 17
Step-by-step explanation:
(a)
Number of green apples = 4
P ( that all three apples are green)
= (limit 4 and 3) / (limit 17 and 3)
= 4! / 3!(4−3)!
= 17! / 3!(17−3)!
= 1 / 170
= 0.005
(b)
Number of red apples = 8
P(that all three apple are green)
=(limit 8 and 3) / (limit 17 and 3)
= 8! / 3!(8−3)!
= 17! / 3!(17−3)!
= 7 / 85
= 0.082
Now,
P(that no three apple is red)= 1−0.082 = 0.918
c)
P(of selecting 4 apple that contain at least 2 red apples)
= (limit 8 and 2) /( limit 17 and 2) X (2/15) + (limit 8 and 3) /(limit 17 / 3) X (1/14)
= (7/34) × (2/15) + (7/85) × (1/14)
= 0.027 + 0.058
= 0.085
d)
P(that the second apple selected is yellow given that the first apple is red)
= (limit 5 and 1) / ( limit 16 and 1)
= 5! / 1!(5−1)!
= 16! / 1!(16−1)!
= 5 /16
= 0.3125
Answer:
a = - 
, b = - 
Step-by-step explanation:
To obtain the required form use the method of completing the square
add/ subtract ( half the coefficient of the x- term)² to x² - 9x
y = x² + 2(- )x + 
- + 14
= (x - )² - + 
= (x - )²- ← in the form (x + a)² + b
with a = - and b = -
If you distribute the 6(x-2) you would get 6x-12 so zero would equal zero
If there aren't any specific requirements for the equation, here are a few choices:
2³ = 8
64 / 8 = 8
2x + 4 = y (where x = 2)
x² - 1 = y (where x = 3)
