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dlinn [17]
1 year ago
10

Which of the binomials below is a factor of this trinomial? x^2 + 3x - 4A. x+4B. x+8C. x-4D. x^2+4

Mathematics
1 answer:
Usimov [2.4K]1 year ago
6 0

Given:

The equation is:

x^2+3x-4

Find-:

Binomials factor of the equation

Explanation-:

The quadratic equation,

x^2+3x-4

Solve for factor

\begin{gathered} =x^2+3x-4 \\  \\ =x^2+4x-x-4 \\  \end{gathered}

Then the factor is:

\begin{gathered} =x^2+4x-x-4 \\  \\ =x(x+4)-1(x+4) \\  \\ =(x+4)(x-1) \end{gathered}

So, the factor is x + 4

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Jonathan is rolling to dice and needs to roll and 11 to win the game he is playing what is the probability that Jonathan wins th
hjlf

Answer:

1 / 18

Step-by-step explanation:

In a roll of two dice :

Number of faces on a dice = 6

Total sample space for 2 6-sided dice = (number of faces)^Number of dice = 6^2 = 36

Total possible outcomes = 36

Required outcome = sum of 11

11 = {(5,6) ; (6, 5)}) = 2 possibilities

Probability = required outcome / Total possible outcomes

P(obtaining a sum of 11) = 2 / 36 = 1/18

5 0
3 years ago
In a store, a sample of 60 pens was selected from a box of 1,200 pens. Of these 60, 4 pens did not work. About how many pens cou
Lapatulllka [165]
Ok so if 1200 total pens and 60 were taken that's a ratio of 1200/60=20

out of 60pens 4 didn't work, again ratio is 4/60=1/15 so about 1/15 of the pens didn't work. 

so we have 1200pens * 1/15broken ratio = 80 pens or we can say 

20*4=80pens won't work from 20 groups of 60 and 4 out of 60 not working is 20*4=80 not working from total batch of 1200.

hope this helps you some! thank you!!!!!!!!!
3 0
3 years ago
The area of a floor to be carpeted is 2700 square feet what is this area in square yards?
Cerrena [4.2K]
C 1yd^2 = 9ft^2 _____yd^2 = 2700ft^2 2700 / 9 = 300 yd^2
5 0
3 years ago
Read 2 more answers
Find the general solution of the given differential equation. cos^2(x)sin(x)dy/dx+(cos^3(x))y=1 g
eimsori [14]

If the given differential equation is

\cos^2(x) \sin(x) \dfrac{dy}{dx} + \cos^3(x) y = 1

then multiply both sides by \frac1{\cos^2(x)} :

\sin(x) \dfrac{dy}{dx} + \cos(x) y = \sec^2(x)

The left side is the derivative of a product,

\dfrac{d}{dx}\left[\sin(x)y\right] = \sec^2(x)

Integrate both sides with respect to x, recalling that \frac{d}{dx}\tan(x) = \sec^2(x) :

\displaystyle \int \frac{d}{dx}\left[\sin(x)y\right] \, dx = \int \sec^2(x) \, dx

\sin(x) y = \tan(x) + C

Solve for y :

\boxed{y = \sec(x) + C \csc(x)}which follows from [tex]\tan(x)=\frac{\sin(x)}{\cos(x)}.

7 0
2 years ago
Help with this pleaseeee​
ELEN [110]

Answer:

(- 3, 37) and (- \frac{5}{2}, \frac{63}{2} )

Step-by-step explanation:

Given the 2 equations

2x² - y + 19 = 0 → (1)

y + 11x = 4 → (2) ← subtract 11x from both sides

y = 4 - 11x → (3)

Substitute y = 4 - 11x into (1)

2x² - (4 - 11x) + 19 = 0

2x² - 4 + 11x + 19 = 0

2x² + 11x + 15 = 0 ← in standard form

(2x + 5)(x + 3) = 0 ← in factored form

Equate each factor to zero and solve for x

2x + 5 = 0 ⇒ 2x = - 5 ⇒ x = - \frac{5}{2}

x + 3 = 0 ⇒ x = - 3

Substitute these values into (3) for corresponding values of y

x = - \frac{5}{2} : y = 4 + \frac{55}{2} = \frac{63}{2} ⇒ (- \frac{5}{2}, \frac{63}{2} )

x = - 3 : y = 4 + 33 = 37 ⇒ (- 3, 37 )

4 0
3 years ago
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