Solve and graph the absolute value inequality: |2x + 4| > 8. number line with open circles on negative 6 and 2, shading in be
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Answer:
Step-by-step explanation:
X no of questions student answers is binomial with n =40 and p =0.5
If approximated to normal, X is Normal with
mean = np = 20 and variance = npq = 10
P(X>N) >0.10
We use std normal distribution table to get z value first then convert to x value
So
This is with continuity correction.
Hence without continuity correction this equals 7.2-0.5 = 6.7
x>6.7
n = 7
f(x) = 2 -4x
Step-by-step explanation:
Step 1 :
Given, f(x) = a(x - h)2 + k
Point on the parabola is (3, 6)
Vertex (h,k) = (1,-2)
Step 2:
Substituting the vertex in the equation we have,
f(x) = a(x-1)2 -2
Substituting the point (3,6) in this we have,
6 = a(3-1)2 - 2 => 6 = 4a -2
=> 4a = 8 => a = 2
Step 3 :
Substituting the value for a and the vertex in the given equation we have
f(x) = 2(x-1)2 -2 = 2(x2 - 2x + 1) -2 = 2x2 - 4x
=> f(x) = 2 -4x which is the standard form