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8 months ago

A taxpayer itemized and deducted an amount in a previous year and

Mathematics

1 answer:

saveliy_v [14]8 months ago

5 0

This is not a form of income it is known as federal tax refund.

What is federal tax refund ?

Tax refunds are issued to taxpayers who have overpaid their taxes, or whose employers have withheld too much from their paychecks.

Therefore, A federal tax refund is not entered on a federal tax return so it is not income. Tax refunds from state governments can be itemized deductions on your federal tax return in the year they are issued.

It must be noted that If you electronically file your tax return or if you file a paper return, your refund is generally issued within 21 days.

check and know more about taxes here :

brainly.com/question/16423331

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Please help me find area of circle

Savatey [412]

Answer:

12.568m^2

Step-by-step explanation:

A=πr^2 where r is. radius

=3.142(2^2)

=3.142(4)

=12.568m^2

5 0

3 years ago

Please help! I'll rate 5 stars, if possible give brainliest, and give a thanks.

muminat

Answer:

2x+20 + x+40 = 180

Step-by-step explanation:

The angles are supplementary so they add to 180

2x+20 + x+40 = 180

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2 years ago

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Graph y≤1−3x. brianly

Daniel [21]

Answer:

Step-by-step explanation:

$\leq$ means everything to the left of, and also everything on the line since it's equal to as well, so B is the correct answer

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3 years ago

A researcher compares the effectiveness of two different instructional methods for teaching electronics. A sample of 138 student

yan [13]

Answer:

The 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for the difference between population means is:

$CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}$

The information provided is as follows:

$n_{1}= 138\\n_{2}=156\\\bar x_{1}=61\\\bar x_{2}=64.6\\\sigma_{1}=18.53\\\sigma_{2}=13.43$

The critical value of <em>z</em> for 98% confidence level is,

$z_{\alpha/2}=z_{0.02/2}=2.326$

Compute the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 as follows:

$CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}$

$=(61-64.6)\pm 2.326\times\sqrt{\frac{(18.53)^{2}}{138}+\frac{(13.43)^{2}}{156}}\\\\=-3.6\pm 4.4404\\\\=(-8.0404, 0.8404)\\\\\approx (-8.04, 0.84)$

Thus, the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

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2 years ago

Solve 9x^2- 17x- 85 = 0 Give your solutions correct to 3 significant figures.

dybincka [34]

Answer:

$x =\frac{17}{18} +\frac{1}{18} \sqrt{3349}$ OR $x =\frac{17}{18} +\frac{-1}{18} \sqrt{3349}$