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puteri [66]
4 years ago
14

The table shows the estimated number of deer living in a forest over a 5 year period. Which type of function best models the dat

a? Write an equation to model the data.
Year/ estimated population
0 | 102
1 | 82
2| 65
3| 52
4 | 42

A. Linear; y=0.8x + 102
B. Quadratic; y=0.8x^2 + 102
C. Exponential; y=102 × 0.8^x
D. Quadratic; y = 102x^2 + 0.8
Mathematics
1 answer:
jek_recluse [69]4 years ago
8 0

Answer:

C ) exponential :  y = 100 * 0.79^x

Step-by-step explanation:

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Please help me with this as soon as possible!!
Pie

Answer:

D. 48

Step-by-step explanation:

Let's first find the probability that in the first 40 trials, exactly two of the coins are heads.

We know that there were 16 such outcomes of 2 heads and 1 tail, and there was a total of 40 possible outcomes. So our probability is:

16 / 40 = 4 / 10 = 2/5

We can assume that the probability that in the next 120 trials, about 2/5 of the outcomes will also be 2 heads and 1 tail. So, we multiply 2/5 by 120 to figure out that exact number:

(2/5) * 120 = 240/5 = 48

The answer is thus D.

3 0
3 years ago
Read 2 more answers
PLZ HELPDONT TROLL IM NICE
marysya [2.9K]

Answer:

0.25y +7y

Step-by-step explanation:

REMEMBER DISTRIBUTION

7 0
3 years ago
Find the slope of the line through the points (-2, -3) and (2, 1).
kiruha [24]

Answer:

1

Step-by-step explanation:

i did it

5 0
3 years ago
I'm struggling, I need your help to find the right answer! (And you get 15 points!)
MAVERICK [17]
Total area =2triangles+3rctangles


rectangles is small ok so
we can consider the 3 rectangles as 1 big reectangle with base 5+12+13=30 and height 8
area=30*8=240

the 2 triangles
the height is 5 becasue it has to to match with the 5 on the small rectangle
base is 12
2 of them
aera=2*1/2*12*5=60


so total
240+60=300

total surfacea area is 300 in^2
7 0
3 years ago
F:[1/2,infinity)—&gt;[3/4,infinity) <br> f(x)=x^2-x+1 <br> find the inverse of f(x);please explain
dexar [7]

Answer:

f^{-1}(x)=\frac{1}{2}+\sqrt{x-\frac{3}{4}}

Step-by-step explanation:

y=x^2-x+1

We want to solve for x.

I'm going to use completing the square.

Subtract 1 on both sides:

y-1=x^2-x

Add (-1/2)^2 on both sides:

y-1+(-1/2)^2=x^2-x+(-1/2)^2

This allows me to write the right hand side as a square.

y-1+1/4=(x-1/2)^2

y-3/4=(x-1/2)^2

Now remember we are solving for x so now we square root both sides:

\pm \sqrt{y-3/4}=x-1/2

The problem said the domain was 1/2 to infinity and the range was 3/4 to infinity.

This is only the right side of the parabola because of the domain restriction. We want x-1/2 to be positive.

That is we want:

\sqrt{y-3/4}=x-1/2

Add 1/2 on both sides:

1/2+\sqrt{y-3/4}=x

The last step is to switch x and y:

1/2+\sqrt{x-3/4}=y

y=1/2+\sqrt{x-3/4}

f^{-1}(x)=1/2+\sqrt{x-3/4}

8 0
3 years ago
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