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olganol [36]
2 years ago
12

A simple random sample is drawn from a normally distributed population. The value of which of the following will not

Mathematics
1 answer:
Bess [88]2 years ago
6 0
Natalie's team needs to make a decision on how to handle a big product recall. People on the team have a lot of strong opinions. Management wants everyone to come to a consensus and to find a solution that everyone can support . What's the best way to get to a consensus ? O a) Everyone on the team talks until the entire team agrees on one decision. Ob ) Everyone on the team discusses options and then votes. Oc ) The team passes the decision - making responsibility to an outside person. d ) The team leader makes a decision without input from the other members .
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Answer:

-3

Step-by-step explanation:

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Answer:

quadrilateral

Step-by-step explanation:

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Nonamiya [84]

Answer:

Step-by-step explanation: do what it says go to a supermarket lol

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3 years ago
two telephone calls come into a switchboard at times that are uniformly distributed in a fixed one-hour period. assume that the
AleksandrR [38]

We wil assume a variable x to be the total number of calls received by the switchboard.

The question also says to assume that the calls were made independently.

Given:

Calls are independent.

Calls are uniformly distributed over a 1 hour period.

Ans (a). The calls are distributed uniformly over 1 hour, hence: (0, 1).

So we have,

f1(x1) = 1

f2(x2) = 1

X1 and X2 are considered to be independent of each other. Hence,

f(x1,x2) = f1 (x1) f2 (x2)

f(x1,x2) = 1 (1)

f(x1,x2) = 1

Thus,

P(X1 <= 0.5; X2 <= 0.5) = ∫0.50 ∫0.50 f(x1,x2) dx2 dx1

= ∫^0.5 0 ∫^0.5 0 (1) dx2 dx1

= ∫^0.5 0 (x2^0.5 0) dx1

= ∫^0.5 0 (0.5 - 0) dx1

= 0.5 ∫^0.5 0 dx1

= 0.5 (x1^0.5 0)

= 0.5 (0.5 - 0)

= 0.25

Therefore, the probability that the calls were received within the first 30 minutes or first half hour is 0.25.

Ans (b). Steps 1 and 2 are the same as the above answer.

Probability = [∫^11/12 0 ∫^x1 + 1/12 x1 1dx2 dx1] + [∫^1 1/12 ∫^x1 x1-1/12 1dx2 dx1

= [∫^11/12 0 (x2 ^x1+1/12 x1 dx1] + [∫^1 1/12 (x2 ^x1 x1-1/12 dx1)]

= [∫^11/12 0 (x1 + 1/12 -x1) dx1] + [∫^1 1/12 (x1 - x1 + 1/12) dx1]

= [(1 + x1/12 - 1) ^11/12 0] + [( 1 - 1 + x1/12) ^1 1/12]

= 11/144 + 11/144

= 0.1528

Therefore, the probability that the calls were received within five minutes of each other is 0.15.

Find more from: brainly.com/question/18125359?referrer=searchResults

#SPJ4

7 0
11 months ago
39. Find the HCF of: 50, 80, and 95​
vesna_86 [32]
I think the answer is 5. The working is in the picture.

4 0
2 years ago
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