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9 months ago

Sketch the graph of each line y= -2

Mathematics

1 answer:

Inessa [10]9 months ago

8 0

The graph of y = -2 is shown below;

Please observe that y is always -2 for any value of x. Hence the graph is a straight line at the point where you have negative 2 on the vertical axis (y-axis).

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<img src="https://tex.z-dn.net/?f=%5Clongmapsto%5Csf%2010%5Ctimes%2010%5Ctimes%2011" id="TexFormula1" title="\longmapsto\sf 10\t

kvv77 [185]

Answer:

100 × 11

1100

Step-by-step explanation:

brainliest plz

3 0

2 years ago

Read 2 more answers

Graph this function: y - 5 = -3(x + 3) Click to select points on the graph.

makvit [3.9K]

Root: (-4/3, 0)
vertical intercept: (0, -4)

6 0

2 years ago

Read 2 more answers

Evaluate the difference quotient for the given function. Simplify your answer.

nasty-shy [4]

I suppose you mean

$f(x) = \dfrac{x+5}{x+1}$

Then

$f(3) = \dfrac{3+5}{3+1} = \dfrac84 = 2$

and the difference quotient is

$\dfrac{f(x)-f(3)}{x-3} = \dfrac{\frac{x+5}{x+1}-2}{x-3} \\\\ \dfrac{f(x)-f(3)}{x-3} = \dfrac{\frac{x+5-2(x+1)}{x+1}}{x-3} \\\\ \dfrac{f(x)-f(3)}{x-3} = \dfrac{-x+3}{(x+1)(x-3)} \\\\ \dfrac{f(x)-f(3)}{x-3} = \boxed{-\dfrac{x-3}{(x+1)(x-3)}}$

If it's the case that x ≠ 3, then (x - 3)/(x - 3) reduces to 1, and you would be left with

$\dfrac{f(x)-f(3)}{x-3}\bigg|_{x\neq3} = -\dfrac1{x+1}$

4 0

1 year ago

In the figure,what’s is m

Sergeeva-Olga [200]

Answer:

∠ DBE = 25.5°

Step-by-step explanation:

Given ∠ DBC = 90° and ∠ DBE + ∠ EBC = ∠ DBC, then

∠ DBE = ∠ DBC - ∠ EBC = 90° - 64.5° = 25.5°

7 0

2 years ago

Help ASAP!!!!!!!!!!!!

zepelin [54]

Answer:

x is greater than or equal to -4

Step-by-step explanation:

I am not sure if I have to graph as well so I will just solve the inequality.

3x-12 greater than or equal to 7x+4

+12 +12

3x is greater than or equal to 7x+16

-7x -7x

-4x is greater than or equal to 16

-4x/-4 16/-4

x is greater than or equal to -4

7 0

2 years ago