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Alex73 [517]
1 year ago
5

Sketch the graph of each line y= -2

Mathematics
1 answer:
Inessa [10]1 year ago
8 0

The graph of y = -2 is shown below;

Please observe that y is always -2 for any value of x. Hence the graph is a straight line at the point where you have negative 2 on the vertical axis (y-axis).

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Which statement is true about the discontinuities of the function f(x)?
Leno4ka [110]

Answer:

  (a)  There are asymptotes at x=3/2 and x=-1/3

Step-by-step explanation:

The denominator zeros can be found by factoring:

  f(x) = (x +1)/((2x -3)(3x +1))

Neither of the denominator factors is cancelled by the numerator factor, so each represents a vertical asyptote, not a function hole.

The asymptotes are at the values of x where the denominator is zero:

  2x -3 = 0   ⇒   x = 3/2

  3x +1 = 0   ⇒   x = -1/3

8 0
2 years ago
CAN SOMEONE PLEASE HELP? THESE QUESTIONS ARE REALLY HARD AND I HAVE BEEN STUCK ON THEM FOR A WHILE. I REVIEWED THE LESSON AND EV
aniked [119]

Well if I did the right calculations... Kim is 24. The sister is age twelve! Hope I helped.

A. K+S=36

B. Well Simple Addition and Subtraction solves this easily. If you Add 12+12 it equals 24. It still needs to be larger so that Kim is twice as old as her little sister. So you Add another 12 which gives you 36. Or you can easily subtract 12 from it and that will also bring you to 24.

6 0
3 years ago
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Bella is buying balloons for a back to school celebration. She sees there are 4
loris [4]

Answer:

The first deal is better because it has more balloons for not too much of a price (individually)

Step-by-step explanation:

15*4= 60

60/18= 3.33

Deal 1= 3.33 for each balloon

10*5= 50

50/16=3.125

3 0
3 years ago
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A store has the following candles in a basket:
Inga [223]
This is your answer.

5 0
3 years ago
What are the real roots of 2x^3+9x^2+4x-15=0
klemol [59]
Well, luckily it is apparent that (x-1) is a root because when x=1 the equation is equal to zero.  So we can divide the equation by that factor to find the other roots. 

(2x^3+9x^2+4x-15)/(x-1)
2x^2  r  11x^2+4x-15
11x    r  15x-15
15     r   0

(x-1)(2x^2+11x+15)=0

(x-1)(2x^2+6x+5x+15)=0

(x-1)(2x(x+3)+5(x+3))=0

(x-1)(2x+5)(x+3)=0

So the roots are x= -3, -2.5, 1
8 0
4 years ago
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