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lana [24]
3 years ago
7

Helppppppppppppppppppppppppppppppppppppp

Mathematics
1 answer:
Lilit [14]3 years ago
5 0

Answer:

would be the first one

Step-by-step explanation:

product means multiplication. so the product of x and 0.28 would be x × 0.28 or 0.28x

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ALRIGHT 66% WE NEED AT LEAST AN 80, WHAT WONDERFUL PERSON IS GONNA HELP!?
bagirrra123 [75]

Answer:

I got 45

Step-by-step explanation:

so I did the triangle first I did 5 times 6 divided by 2 and got 15 then I did 5 times 6 and got 30 then I added the 30 and 15 together.

7 0
3 years ago
Read 2 more answers
Select all the correct equations.
Naya [18.7K]

Answer:

You did not post the options, but i will try to answer this in a general way.

Because we have two solutions, i know that we are talking about quadratic equations, of the form of:

0 = a*x^2 + b*x + c.

There are two easy ways to see if the solutions of this equation are real or not.

1) look at the graph, if the graph touches the x-axis, then we have real solutions (if the graph does not touch the x-axis, we have complex solutions).

2) look at the determinant.

The determinant of a quadratic equation is:

D = b^2 - 4*a*c.

if D > 0, we have two real solutions.

if D = 0, we have one real solution (or two real solutions that are equal)

if D < 0, we have two complex solutions.

3 0
4 years ago
Himpunan penyelesaian pertidaksamaan nilai mutlak |2x-4| &gt; |3x+2|
Stells [14]

Answer:

The solution in interval notation is:

(-6,\frac{2}{5}).

The solution in inequality notation is:

-6.

Step-by-step explanation:

I think you are asking how to solve this for x.

Keep in mind |x|=\sqrt{x^2}.

|2x-4|>|3x+2|

\sqrt{(2x-4)^2}>\sqrt{(3x+2)^2}

If \sqrt{u}>\sqrt{v} then u>v.

(2x-4)^2>(3x+2)^2

Subtract (2x-4)^2 on both sides:

0>(3x+2)^2-(2x-4)^2

Factor the difference of squares a^2-b^2=(a-b)(a+b):

0>((3x+2)-(2x-4))((3x+2)+(2x-4))

Simplify inside the factors:

0>(x+6)(5x-2)

(x+6)(5x-2)

The left hand side is a parabola that faces up.  I know this because the degree is 2.  

The zeros of the the parabola are at x=-6 and x=2/5.

We can solve x+6=0 and 5x-2=0 to reach that conclusion.

x+6=0

Subtract 6 on both sides:

x=-6

5x-2=0

Add 2 on both sides:

5x=2

Divide both sides by 5:

x=2/5

Since the parabola faces us and (x+6)(5x-2) then we are looking at the interval from x=-6 to x=2/5 as our solution.  That part is where the parabola is below the x-axis.  We are looking for where it is below since it says the where is the parabola<0.

The solution in interval notation is:

(-6,\frac{2}{5}).

The solution in inequality notation is:

-6.

6 0
4 years ago
Help me please and thank you.​
11111nata11111 [884]

Answer:

The constant term is 6

The x³ term has a coeficient of 12

The resulting polynomial has degree 4

7 0
3 years ago
Which number produces an irrational number?
blondinia [14]
Your answer is c. 0.5454545... because an irrational number is one that repeats itself.
3 0
4 years ago
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