All categories

1 year ago

PLEASE HELP ASAP I WILL GIVE BRAINLIEST Find x and y

Mathematics

1 answer:

borishaifa [10]1 year ago

7 0

The values of the variables x and y in the triangle are 1.25 and 1.75

<h3>How to determine the values of the variables x and y?</h3>

The tringle represents the given parameter

On the triangle, we have the following equivalent ratio

5 : 8 = 5 + x : 10

7 : 8 = 7 + y : 10

These are true because the horizontal lines of the triangles are parallel

So, we have

5 : 8 = 5 + x : 10

Express as fraction

5/8 = 5 + x/10

This gives

5 + x = 6.25

Solve for x

x = 1.25

Similarly, we have

7 : 8 = 7 + y : 10

So, we have

7/8 = 7 + y/10

This gives

7 + y = 10*7/8

Evaluate

7 + y = 8.75

So, we have

y = 1.75

Hence, the values of x and y are 1.25 and 1.75

You might be interested in

Please help<br> It wants to know what the median of the data is.

SVETLANKA909090 [29]

Your median should be 40 in this since you’re using a box and whisker plot.

4 0

3 years ago

Read 2 more answers

Karina needs a total of $45 to buy her mother a birthday present. She has saved 20% of the amount so far. How much has she saved

CaHeK987 [17]

Answer:

Step-by-step explanation:

20% of 45 is 9.

4 0

3 years ago

Read 2 more answers

A competitive knitter is knitting a circular place mat. The radius of the mat is given by the formula

Ilia_Sergeevich [38]

Answer: A. $A'(t)=\frac{4356\pi}{(t+11)^{3}}-\frac{527076\pi}{(t+11)^{5}}$

B. A'(5) = 1.76 cm/s

Step-by-step explanation: <u>Rate</u> <u>of</u> <u>change</u> measures the slope of a curve at a certain instant, therefore, rate is the derivative.

A. Area of a circle is given by

$A=\pi.r^{2}$

So to find the rate of the area:

$\frac{dA}{dt}=\frac{dA}{dr}.\frac{dr}{dt}$

$\frac{dA}{dr} =2.\pi.r$

Using $r(t)=3-\frac{363}{(t+11)^{2}}$

$\frac{dr}{dt}=\frac{726}{(t+11)^{3}}$

Then

$\frac{dA}{dt}=2.\pi.r.[\frac{726}{(t+11)^{3}}]$

$\frac{dA}{dt}=2.\pi.[3-\frac{363}{(t+11)^{2}}].\frac{726}{(t+11)^{3}}$

Multipying and simplifying:

$\frac{dA}{dt}=\frac{4356\pi}{(t+11)^{3}} -\frac{527076\pi}{(t+11)^{5}}$

The rate at which the area is increasing is given by expression $A'(t)=\frac{4356\pi}{(t+11)^{3}} -\frac{527076\pi}{(t+11)^{5}}$ .

B. At t = 5, rate is:

$A'(5)=\frac{4356\pi}{(5+11)^{3}} -\frac{527076\pi}{(5+11)^{5}}$

$A'(5)=\frac{4356\pi}{4096} -\frac{527076\pi}{1048576}$

$A'(5)=\frac{2408693760\pi}{4294967296}$

$A'(5)=1.76268$

At 5 seconds, the area is expanded at a rate of 1.76 cm/s.

5 0

2 years ago

What is the volume of a cone with radius 7 cm and height 11 cm? Round your answer to two decimal places.

a_sh-v [17]

Answer:

D. 564.44 cm^3

Step-by-step explanation:

V = (1/3)(pi)r^2h

V = (1/3)(3.14159)(7 cm)^2(11 cm)

V = 564.44 cm^3

5 0

3 years ago

Which of the following are adjacent angles?

andriy [413]

Answer:

Step-by-step explana i think its right

3 0

3 years ago