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3 years ago

Write and solve an equation to find x. Q (11x - 5) P (6x + 5) R x

Mathematics

1 answer:

makkiz [27]3 years ago

3 0

Answer:

x = 10 degrees

Step-by-step explanation:

the sum of angles in triangle = 180 degrees

11x - 5 + 6x + 5 + x = 180

combine

18x = 180

divide

x = 10 degrees

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A local college offers scholarships to students who graduate in the top 1% of their high school classes according to GPA. If a h

tangare [24]

Answer:

4 students would be eligible for the scholarships

Step-by-step explanation:

4 0

3 years ago

a cup was filled at a constant rate. it started empty. after 2 seconds, it held 70 cm cubes of water. the radius is 4 and te hei

Viktor [21]

Answer:

89.51%

Step-by-step explanation:

Assuming given units are in cm

Tge rate of filling the cup is 70/2= 35 cm3/s

Volume of the cup is $\pi r^{2}\frac {h}{3}$ and replacing r with 4 cm and h with 7 cm then the volume is equivalent to

$\pi*4^{2}*\frac {7}{3}= 117.3 cm^{3}$

Volume filled after 3 seconds will be 3*35=105 cm3

Percentage filled is $\frac {105}{117.3}\times 100\approx 89.51$

8 0

3 years ago

Need help with this

Vlad1618 [11]

Answer:

Step-by-step explanation:

5 0

3 years ago

3. The adult men of the Dinaric Alps have the highest average height of all regions. The

ahrayia [7]

Using the normal distribution, it is found that:

3 - a) The 40th percentile of the height of Dinaric Alps distribution for men is of 72.2 inches.

3 - b) The minimum height of man in the Dinaric Alps that would place him in the top 10% of all heights is of 76.84 inches.

4 - a) The 25th percentile for the math scores was of 71.6 inches.

4 - b) The 75th percentile for the math scores was of 78.4 inches.

<h3>Normal Probability Distribution </h3>

In a normal distribution with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

It measures how many standard deviations the measure is from the mean.

After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

Question 3:

The mean is of 73 inches, hence $\mu = 73$ .

The standard deviation is of 3 inches, hence $\sigma = 3$ .

Item a:

The 40th percentile is X when Z has a p-value of 0.4, so X when Z = -0.253.

$Z = \frac{X - \mu}{\sigma}$

$-0.253 = \frac{X - 73}{3}$

$X - 73 = -0.253(3)$

$X = 72.2$

The 40th percentile of the height of Dinaric Alps distribution for men is of 72.2 inches.

Item b:

The minimum height is the 100 - 10 = 90th percentile is X when Z has a p-value of 0.9, so X when Z = 1.28.

$Z = \frac{X - \mu}{\sigma}$

$1.28 = \frac{X - 73}{3}$

$X - 73 = 1.28(3)$

$X = 76.84$

The minimum height of man in the Dinaric Alps that would place him in the top 10% of all heights is of 76.84 inches.

Question 4:

The mean score is of 75, hence $\mu = 75$ .

The standard deviation is of 5, hence $\sigma = 5$ .

Item a:

The 25th percentile is X when Z has a p-value of 0.25, so X when Z = -0.675.

$Z = \frac{X - \mu}{\sigma}$

$-0.675 = \frac{X - 75}{5}$

$X - 75 = -0.675(5)$

$X = 71.6$

The 25th percentile for the math scores was of 71.6 inches.

Item b:

The 75th percentile is X when Z has a p-value of 0.25, so X when Z = 0.675.

$Z = \frac{X - \mu}{\sigma}$

$0.675 = \frac{X - 75}{5}$

$X - 75 = 0.675(5)$

$X = 78.4$

The 75th percentile for the math scores was of 78.4 inches.

To learn more about the normal distribution, you can take a look at brainly.com/question/24663213

5 0

2 years ago

For his long distance phone service, Keith pays a $3 monthly fee plus 11 cents per minute. Last month, Keith's long distance bil

Allushta [10]

The number of minutes for which Keith was billed = 97

Step-by-step explanation:

Step 1:

It is given that Keith pays a fixed fee of 3$ a month and 11 cents per minute for the number of minutes used.

Total cost = Fixed cost + Per minute cost

If x represents the number of minutes consumed in a month then we can compute the total cost using the below equation:

Total cost = 3$ + 0.11 * x

Step 2:

The total cost is 13.67$

Substituting in the equation we get

13.67 = 3 + 0.11 * x

x = 10.67 / 0.11 = 97 minutes

Step 3:

Answer:

The number of minutes for which Keith was billed = 97

3 0

3 years ago