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Fiesta28 [93]
3 years ago
8

Khan Academy’s question

Mathematics
1 answer:
prisoha [69]3 years ago
6 0

Answer:

Black Screen so sorry

Step-by-step explanation:

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Number 13 please. I know the answer is 20 I just don’t know how to get there
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4/20 is 0.20, which is equivalent to 20%.


Remember that 1.0=100%, 0.5=50%, 0.2=20%, 0.05=5%, and so on.

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3 * 9 + (6 + 5 – 3) – 12 : 4 =
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Answer:

23,4

Step-by-step explanation:

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Secants P N and L N intersect at point N outside of the circle. Secant P N intersects the circle at point Q and secant L N inter
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A circle is shown. Secants P N and L N intersect at point N outside of the circle. Secant P N intersects the circle at point Q and secant L N intersects the circle at point M. The length of P N is 32, the length of Q N is x, the length of L M is 22, and the length of M N is 14.

In the diagram, the length of the external portion of the secant segment PN is <u>X</u>

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Step-by-step explanation:

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3 years ago
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You want to place a towel bar that is 24 1/4 centimeters long in the center of a door that is 70 1/3 centimeters wide. How far s
Aleksandr [31]

Answer:

The towel bar should be placed at a distance of 23\frac{1}{24}\ cm from each edge of the door.

Step-by-step explanation:

Given:

Length of the towel bar = 24\frac14\ cm

Now given length is in mixed fraction we will convert in fraction.

To Convert mixed fraction into fraction Multiply the whole number part by the fraction's denominator, then Add that to the numerator, then write the result on top of the denominator.

24\frac14\ cm can be Rewritten as \frac{97}{4}\ cm

Length of the towel bar =  \frac{97}{4}\ cm

Length of the door = 70 \frac13\ cm

70 \frac13\ cm can be Rewritten as \frac{211}{3}\ cm

Length of the door = \frac{211}{3}\ cm

We need to find the distance bar should be place at from each edge of the door.

Solution:

Let the distance of bar from each edge of the door be 'x'.

 So as we placed the towel bar in the center of the door it divides into two i.e. '2x'

Now we can say that;

\frac{97}{4}+2x=\frac{211}{3}\\\\2x=\frac{211}{3}-\frac{97}{4}

Now we will take LCM to make the denominators common we get;

2x=\frac{211\times4}{3\times4}-\frac{97\times3}{4\times3}\\\\\\2x= \frac{844}{12}+\frac{281}{12}

Now denominators are common so we will solve the numerators.

2x =\frac{844-291}{12}\\\\2x=\frac{553}{12}\\\\x=\frac{553}{12\times2} =\frac{553}{24}

Or x=23\frac{1}{24}\ cm

Hence The towel bar should be placed at a distance of 23\frac{1}{24}\ cm from each edge of the door.

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A counterexample is a specific case which shows that a general statement is false. Example 1: Provide a counterexample to show that the statement. "Every quadrilateral has at least two congruent sides" is not always true.

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