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2 years ago

You have proveGraph the image of rectangle RSTU after a translation 4 units down.

Mathematics

1 answer:

rodikova [14]2 years ago

4 0

After the translation 4 units down

The rule of translation is (x, y) to (x , y-4)

The graph will be as following

============================================================================

For the graph of the triangle:

D = ( 4 , 0) , B = (6 , -2) and C = ( 10 , -2)

it is required to graph after translation 7 units left and 8 units up

So, for each point add ( -7 , 8 )

So,

D' = ( -3 , 8) , B' = (-1 , 6 ) and C' = ( 3 , 6)

the graph will be as following:

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Health insurance benefits vary by the size of the company (the Henry J. Kaiser Family Foundation website, June 23, 2016). The sa

xxMikexx [17]

Answer:

$\chi^2 = \frac{(32-42)^2}{42}+\frac{(18-8)^2}{8}+\frac{(68-63)^2}{63}+\frac{(7-12)^2}{12}+\frac{(89-84)^2}{84}+\frac{(11-16)^2}{16}=19.221$

Now we can calculate the degrees of freedom for the statistic given by:

$df=(rows-1)(cols-1)=(3-1)(2-1)=2$

And we can calculate the p value given by:

$p_v = P(\chi^2_{2} >19.221)=0.000067$

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(19.221,2,TRUE)"

Since the p values is higher than a significance level for example $\alpha=0.05$ , we can reject the null hypothesis at 5% of significance, and we can conclude that the two variables are dependent at 5% of significance.

Step-by-step explanation:

Previous concepts

A chi-square goodness of fit test "determines if a sample data matches a population".

A chi-square test for independence "compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each another".

Solution to the problem

Assume the following dataset:

Size Company/ Heal. Ins. Yes No Total

Small 32 18 50

Medium 68 7 75

Large 89 11 100

_____________________________________

Total 189 36 225

We need to conduct a chi square test in order to check the following hypothesis:

H0: independence between heath insurance coverage and size of the company

H1: NO independence between heath insurance coverage and size of the company

The statistic to check the hypothesis is given by:

$\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}$

The table given represent the observed values, we just need to calculate the expected values with the following formula $E_i = \frac{total col * total row}{grand total}$

And the calculations are given by:

$E_{1} =\frac{50*189}{225}=42$

$E_{2} =\frac{50*36}{225}=8$

$E_{3} =\frac{75*189}{225}=63$

$E_{4} =\frac{75*36}{225}=12$

$E_{5} =\frac{100*189}{225}=84$

$E_{6} =\frac{100*36}{225}=16$

And the expected values are given by:

Size Company/ Heal. Ins. Yes No Total

Small 42 8 50

Medium 63 12 75

Large 84 16 100

_____________________________________

Total 189 36 225

And now we can calculate the statistic:

$\chi^2 = \frac{(32-42)^2}{42}+\frac{(18-8)^2}{8}+\frac{(68-63)^2}{63}+\frac{(7-12)^2}{12}+\frac{(89-84)^2}{84}+\frac{(11-16)^2}{16}=19.221$

Now we can calculate the degrees of freedom for the statistic given by:

$df=(rows-1)(cols-1)=(3-1)(2-1)=2$

And we can calculate the p value given by:

$p_v = P(\chi^2_{2} >19.221)=0.000067$

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(19.221,2,TRUE)"

3 0

3 years ago

-b - 7?

Olegator [25]

Answer:

4 better xplanation inbox

Step-by-step explanation:

8 0

3 years ago

Jack leased a car for $159/month for 36 months. The amount due when he signed the lease was $2399. How much did Jack pay during

ArbitrLikvidat [17]

Quick question before I answer: Did he have to pay $2,399 when he signed the lease, or was that just how much he had to pay in total over the course of 36 months?

6 0

3 years ago

Joshua walked 14 feet down the hall of his house to get the door he continued in a straight line out the door and across the yar

AleksandrR [38]

Answer:

Joshua walked 48 feet in total.

Step-by-step explanation:

To find the total distance we need to sum every distance that he walked. We have:

- First: Joshua walked down the hall to the door = 14 feet

- Second: He continued in a straight line out the door and across the yard to the mailbox = 24 feet

- Third: He came straight back across the yard and stopped to pet his dog = 10 feet

Hence, the total distance is:

$d_{T} = d_{1} + d_{2} + d_{3} = 14 ft + 24 ft + 10 ft = 48 ft$

Therefore, Joshua walked 48 feet in total.

I hope it helps you!

8 0

3 years ago

What is the solution to -55+q=7 A. a=-62 B. q=62 C. q=42 D. q=-42

Scorpion4ik [409]

Answer:

C, as q = 62.

Step-by-step explanation:

When you have an equation, your goal is to get the letter you are solving for alone. To do this, you employ a simple rule: what you do to one side of the equals sign, you must do the other.

To isolate q in -55 + q = 7, you must add 55 to the left side. q is now alone. However, because we added 55 to the left side, we must also do it to the right! 7 + 55 = 62, so the new right side is 62. Hence, we get to this:

q = 62

The answer is now in plain sight!

4 0

3 years ago

Read 2 more answers