Answer:
A) A(t) = 4500*π - 1600*t
B) A(4) = 7730 in³
C) t = 8,8 sec
Step-by-step explanation:
The volume of the sphere is:
d max = 30 r max = 15 in
V(s) = (4/3)*π*r³ V(s) = (4/3)*π* (15)³
V(s) = 4500*π
A) Amount of air needed to fill the ball A(t)
A(t) = Total max. volume of the sphere - rate of flux of air * time
A(t) = 4500*π - 1600*t in³
B) After 4 minutes
A(4) = 4500*π - 6400
A(4) = 14130 - 6400
A(4) = 7730 in³
C) A(t) = 4500*π - 1600*t
when A(t) = 0 the ball got its maximum volume then:
4500*π - 1600*t = 0
t = 14130/1600
t = 8,8 sec
Well you never sent a picture but the most logical answer is 80 cm
Answer:
0.03
27
Step-by-step explanation:
Use the formula y=mx+b
m= slope
b= y-int
Rate of change can also be interpreted as the slope.
0.03
The initial value can be interpreted as the y-intercept.
27
Answer:
$98.4.
Step-by-step explanation:
Since the university has decided that for the following year lecture costs will increase by 20%, workshop costs by 10%, and examination costs will stay the same, and that for level 2 the current hourly costs are 10, 24, and 60 respectively To determine how much the level 2 course cost in the following year, the following calculation must be performed:
10 x 1.2 + 24 x 1.1 + 60 = X
12 + 26.4 + 60 = X
98.4 = X
Thus, the level 2 course will cost $ 98.4 next year.
X^2+12x+6=0 subtract 6 from both sides...
x^2+12x=-6 halve linear coefficient, square it, and add it to both sides...
x^2+12x+36=30 now the left side is a perfect square...
(x+6)^2=30 take square root of both sides...
x+6=30^(1/2) subtract 6 from both sides...
x=-6-30^(1/2) and -6+30^(1/2)
