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ehidna [41]
11 months ago
11

Joey walked 10 laps around the school's track. He walked a total distance of 6.74 miles. Monica walked 30 laps around the same t

rack. What is the total distance Monica walked?
Mathematics
1 answer:
Anvisha [2.4K]11 months ago
3 0

Answer:

20.22 miles

Step-by-step explanation:

If 10 laps is 6.74 then 30 laps is 3*6.74 which is 20.22

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5,1,0,4,0 what is the range?
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range: 4

Step-by-Step Explanation:

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Can u pls help me with this question ​
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three-quarters of a pile of bricks were used for a certain project. when two thirds of the reminder had been used, 50 bricks wer
kati45 [8]

Answer:

600

Step-by-step explanation:

Let's consider this question using algebra.

Imagine the number of bricks in the original pile is x.

We are told that \frac{3}{4} of the bricks are used for a project, meaning that \frac{3}{4} x has been used, leaving us with \frac{1}{4}x as our remainder.

Then, we are told that \frac{2}{3} of the remainder are used to leave us with 50 bricks. This means that \frac{1}{3} of the remainder is left, and this is equal to 50 bricks. This means that the remainder's original amount is equal to 150, because we are told that \frac{1}{3} of the remainder is equal to 50.

So, we know that the remainder is 150, and we also know that the remainder is \frac{1}{4} x. Let's now use these to form an equation.

\frac{1}{4} x = 150

Because we know that a quarter of the original amount of bricks is equal to 150, we can multiply both sides of the equation by 4 to get the original amount of bricks in the pile.

x = 150 * 4 = 600

So, there were 600 bricks in the original pile.

8 0
1 year ago
Complete the missing parts of the
vekshin1

Answer:

Remember the property:

a^-1 = (1/a)^1

and:

(a/b)^n = (a^n)/(b^n)

A table for a function like:

\left[\begin{array}{ccc}x&f(x)\\&\\&\\&\\&\end{array}\right]

Is just completed as:

\left[\begin{array}{ccc}x&f(x)\\x_1&f(x_1)\\x_2&f(x_2)\\x_3&f(x_3)\\x_4&f(x_4)\end{array}\right]

So, here we have:

y = f(x) = (1/6)^x

To complete the table, we need to find:

f(-1)

and

f(2)

So let's find these two values:

f(-1) = (1/6)^-1 = (6/1)^1 = 6

and the other value is:

f(2) = (1/6)^2 = 1/36

Then the complete table is:

\left[\begin{array}{ccc}x&f(x)\\-2&36\\-1&6\\0&1\\1&1/6\\2&1/36\\1&1/216\end{array}\right]

4 0
2 years ago
Solve for x in the triangle. Round your answer to the nearest tenth.
Pavel [41]

Answer:

<h3>6.5</h3>

Step-by-step explanation:

The triangle shown is right angles where;

opposite side = x

adjacent side = 8

Angle of elevation = 39°

Using TOA trigonometry identity

tan 39° = opp/hyp

tan 39° = x/8

x = 8tan39°

x = 6.48

<em>Hence the value of x is 6.5 to the nearest tenth</em>

5 0
2 years ago
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