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matrenka [14]
1 year ago
14

Suppose you invest $5,000 at 4% annual interest. How much money would your investment be worth after 10 years? Round your answer

to the nearest hundredth (2 places after the decimal).
Mathematics
1 answer:
katrin2010 [14]1 year ago
4 0

The investment will be worth $7,401.22 after 10 years

Here, we want to calculate the amount the investment will be worth after 10 years

Mathematically, to get this, we will use the compound interest formula;

A\text{ = P(1 + }\frac{r}{n})^{nt}

where A is the amount after 10 years

P is the amount invested which is $5,000

r is the interest rate which is 4%, same as 4/100 = 0.04

n is the number of terms yearly the investment will be compounded. Since the interest rate is annual, then the number of times it will be compounded yearly is 1

t is the number of years which is 10 in this case

Substituting these values, we have;

\begin{gathered} A\text{ =5000 (1 + }\frac{0.04}{1})^{1\times10} \\  \\ A=5000(1+0.04)^{10} \\  \\ A=5000(1.04)^{10} \\  \\ A\text{ = 7,401.22} \end{gathered}

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Find the first three terms in the expansion , in ascending power of x , of (2+x)^6 and obtain the coefficient of x^2 in the expa
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Answer:

The first 3 terms in the expansion of (2 + x)^{6} , in ascending power of x are,

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Step-by-step explanation:

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so, the first 3 terms in the expansion of (2 + x)^{6} , in ascending power of x are,

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for k = 5, the coefficient of  x^{2}  is , (-32) \times 6 = -192

for k = 6 , the coefficient of x^{2} is, 6_{C_{2}} \times 2^{4} = 240

so,   coefficient of x^{2} in the final expression = (240 - 192) = 48

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