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1 year ago

In the morning, the temperature in Westfield City was

Mathematics

1 answer:

Thepotemich [5.8K]1 year ago

4 0

Martin's answer is wrong. The afternoon temperature in Westfield city is -10°F.

Given,

The temperature in Westfield city in morning = -2°F

The drop down temperature by afternoon = 8°F

We have to find the temperature in afternoon:

Temperature in afternoon = Temperature in morning - Drop down temperature

= -2 - 8 = -10

The afternoon temperature in Westfield city is -10°F

Martin subtracted like:

-2 - (-8) = -2 + 8 = 6

This is wrong.

That is,

We can conclude like:

Martin's answer is wrong. The temperature in Westfield city in afternoon is -10°F

Learn more about temperature here:

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Step-by-step explanation:

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Summation(x - mean)² = (29.7 - 29.7875)^2 + (29.4 - 29.7875)^2 + (31.7 - 29.7875)^2 + (29.0 - 29.7875)^2 + (29.1 - 29.7875)^2 + (30.5 - 29.7875)^2 + (29.1 - 29.7875)^2 + (29.8 - 29.7875)^2 = 5.88875

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a) We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean

For the null hypothesis,

H0:µ ≤ 30000

For the alternative hypothesis,

H1:µ > 30000

This is a right tailed test.

b) The decision rule is to reject the null hypothesis if the significance level of 0.05 is greater than the probability value. If it is otherwise, we would fail to reject the null hypothesis.

c) Since the number of samples is small and no population standard deviation is given, the distribution is a student's t.

Since n = 8

Degrees of freedom, df = n - 1 = 8 - 1 = 7

t = (x - µ)/(s/√n)

Where

x = sample mean = 29787.5

µ = population mean = 30000

s = samples standard deviation = 880

t = (29787.5 - 30000)/(880/√8) = - 0.68

We would determine the p value using the t test calculator. It becomes

p = 0.26

d) Since alpha, 0.1 < the p value, 0.26, then we would fail to reject the null hypothesis.

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