Before we can make sure that E is correct, we need to make the denominator is equal with questions and the choices or convert into decimal.
2/3 = 0.66
1/3=0.33
1/5=0.2
2/6=1/3 = 0.33
1/2 = 0.5
7/10 = 0.7
7/9 = 0.77
The question is :
2/3 < x < 7/9
0.66 < x < 0.77
We need to divide into 2 parts :
0.66 < x
x < 0.77
So we need to find the answer that x is greater that 0.66 and we got 7/10. And 7/10 is less than 7/9.
Hope this helps. Please ask if you don't understand.
Answer:
My best guess will have to be B
Step-by-step explanation:
i remember this question
Answer:
The distance covered is 113.75 m
Step-by-step explanation:
As per the question:
The initial velocity of the train, v = 20 m/s
The final velocity of the train, v' = 6 m/s
Uniform deceleration, a = 1.6![m/s^{2}](https://tex.z-dn.net/?f=m%2Fs%5E%7B2%7D)
Or uniform acceleration, a = - 1.6![m/s^{2}](https://tex.z-dn.net/?f=m%2Fs%5E%7B2%7D)
<em>Here, the body decelerates, i.e., slows down at a uniform rate thus we take acceleration with negative sign.</em>
Now, to find the distance covered, s:
Using the eqn of Kinemetics:
![v'^{2} = v^{2} + 2as](https://tex.z-dn.net/?f=v%27%5E%7B2%7D%20%3D%20v%5E%7B2%7D%20%2B%202as)
![6^{2} = 20^{2} + 2(- 1.6)s](https://tex.z-dn.net/?f=6%5E%7B2%7D%20%3D%2020%5E%7B2%7D%20%2B%202%28-%201.6%29s)
![36 - 400 = - 3.6s](https://tex.z-dn.net/?f=36%20-%20400%20%3D%20-%203.6s)
![s = \frac{- 364}{- 3.6} = 113.75\ m](https://tex.z-dn.net/?f=s%20%3D%20%5Cfrac%7B-%20364%7D%7B-%203.6%7D%20%3D%20113.75%5C%20m)
Answer:
111 & 82
Step-by-step explanation:
888/8=111
574/7=82
Answer:D
Step-bDy-step explanation:
easy