Answer:
11/12 = 3/4
Step-by-step explanation:
sorry that's the only one I know :(
Answer:
The answer is 176
Step-by-step explanation:
Multiply 16 by 11.
F = t ⇨ df = dt
dg = sec² 2t dt ⇨ g = (1/2) tan 2t
⇔
integral of t sec² 2t dt = (1/2) t tan 2t - (1/2) integral of tan 2t dt
u = 2t ⇨ du = 2 dt
As integral of tan u = - ln (cos (u)), you get :
integral of t sec² 2t dt = (1/4) ln (cos (u)) + (1/2) t tan 2t + constant
integral of t sec² 2t dt = (1/2) t tan 2t + (1/4) ln (cos (2t)) + constant
integral of t sec² 2t dt = (1/4) (2t tan 2t + ln (cos (2t))) + constant ⇦ answer
Step-by-step explanation:
Xj + Xk/2 = Xm
7 + Xk/2 = 1
to get rid of the bracket, multiply all two sides by the denominator.
2(7 + Xk/2) = 1(2)
7 + Xk = 2
Xk = 2 - 7
Xk = -5
Yj + Yk/2 = Ym
2 + Yk/2 = -2
to get rid of the bracket, multiply all two sides by the denominator.
2(2 + Yk/2) = -2(2)
2 + Yk = -4
Yk = -4 - 2
Yk = -6
Therefore the coordinates of point K is (-5,-6)
Answer:
<h2>61°</h2>
Step-by-step explanation:
Use the sine law:

We have:

Substitute:
<em>cross multiply</em>

<em>divide both sides by 6</em>
