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11 months ago

I need help with this practice problem solving This is trigonometry from my ACT prep guide

Mathematics

1 answer:

Novay_Z [31]11 months ago

6 0

Take into account, that in general, a cosine function of amplitude A, period T and vertical translation b, can be written as follow:

$f(x)=A\cos (\frac{2\pi}{T}x)+b$

In the given case, you have:

A = 4

T = 3π/4

b = -3

By replacing you obtain:

$\begin{gathered} f(x)=4\cos (\frac{2\pi}{\frac{3\pi}{4}}x)-3 \\ f(x)=4\cos (\frac{8}{3}x)-3 \end{gathered}$

Hence, the answer is:

f(x) = 4cos(8/3 x) - 3

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What is the domain of the function represented by these ordered pairs?

insens350 [35]

Answer:

A. {-2, -1, 0, 3, 5}

Step-by-step explanation:

The domain is the set containing the x-coordinates of all the points of the function.

{(-2, 1), (0, 0), (3, -1) (-1, 7), (5, 7)}

Domain: {-2, -1, 0, 3, 5}

4 0

3 years ago

Read 2 more answers

Please find the value of x and y.

Sophie [7]

Answer:

x = 11

y = 3

Step-by-step explanation:

4y+1=6y-5

-4y -4y

+1 =2y-5

+5 +5

6/2=2y/2

3=y

2x-4= 18

+4 +4

2x/2 = 22/2

x=11

7 0

3 years ago

a man has a garden measuring 84 metre by 56 he want to divide them equally into the minimum number of square plot what is the le

maw [93]

Answer:

Step-by-step explanation:

84 = 3 x 28

56 = 2 x 28

Minimum number of square plot, each square is 28 x 28

the number is 3 x 2 = 6

8 0

2 years ago

Pleases someone explain

Nikolay [14]

When you have a negative exponent, you move the base with the negative exponent to the other side of the fraction to make the exponent positive.

For example:

$\frac{1}{y^{-2}} =\frac{y^2}{1}$ or $y^2$

$2x^{-3}$ or $\frac{2^1x^{-3}}{1} =\frac{2}{x^3}$

$\frac{1}{x^{-5}} =x^5$

When a base with an exponent is divided by a base with an exponent, you subtract the exponents together. (But you can only combine the exponents when the bases are the same)

For example:

$\frac{x^2}{y}$ (can't combine because they have different bases of y and x)

$\frac{x^5}{x^3} =x^{(5-3)}=x^2$

$\frac{2^2}{2} =2^{(2-1)}=2^1 = 2$

When you multiply an exponent directly to a base with an exponent, you multiply the exponents together.

For example:

$(x^2)^3=x^{(2*3)}=x^6$

$(y^2)^{10}=y^{(2*10)}=y^{20}$

$\frac{2e^0}{(e^{-3})^2}$ First multiply the exponents together in the denominator

$\frac{2e^0}{e^{(-3*2)}}= \frac{2e^0}{e^{-6}}$ Now subtract the exponents together

$2e^{(0-(-6))}$ (two negative signs cancel each other out and become positive)

$2e^{(0+6)}$

$2e^6$

7 0

3 years ago

-2(8) ÷ (-4) What is the answer

olganol [36]

Answer:

The given expression 2(8) ÷ (-4) = 4

Step-by-step explanation:

Here, the given expression is : -2(8) ÷ (-4)

Now,we also know that $a \div b = a \times \frac{1}{b}$

So, here $-2(8) \div (-4) = -2(8) \times \frac{1}{(-4)} = \frac{-16}{-4} = 4$

⇒ The given expression -2(8) ÷ (-4) = 4

7 0

3 years ago