The graph represents y=-4x-1
If you notice the line, it goes past the -1 on the y axis which indicates that the y intercept is -1 since that was the only choice which displayed this, we know that our answer is y=-4x-1
Answer:
a. ∀x (User(x) → (∃y (Mailbox(y) ∧ Access(x, y))))
b. FileSystemLocked → ∀x Access(x, SystemMailbox)
c. ∀x ∀y ((Firewall(x) ∧ Diagnostic(x)) → (ProxyServer(y) → Diagnostic(y))
d. ∀x (ThroughputNormal ∧(ProxyServer(x)∧ ¬Diagnostic(x))) → (∃y Router(y)∧Functioning(y))
Step-by-step explanation:
a)
Let the domain be users and mailboxes. Let User(x) be “x is a user”, let Mailbox(y) be “y is a mailbox”, and let Access(x, y) be “x has access to y”.
∀x (User(x) → (∃y (Mailbox(y) ∧ Access(x, y))))
(b)
Let the domain be people in the group. Let Access(x, y) be “x has access to y”. Let FileSystemLocked be the proposition “the file system is locked.” Let System Mailbox be the constant that is the system mailbox.
FileSystemLocked → ∀x Access(x, SystemMailbox)
(c)
Let the domain be all applications. Let Firewall(x) be “x is the firewall”, and let ProxyServer(x) be “x is the proxy server.” Let Diagnostic(x) be “x is in a diagnostic state”.
∀x ∀y ((Firewall(x) ∧ Diagnostic(x)) → (ProxyServer(y) → Diagnostic(y))
(d)
Let the domain be all applications and routers. Let Router(x) be “x is a router”, and let ProxyServer(x) be “x is the proxy server.” Let Diagnostic(x) be “x is in a diagnostic state”. Let ThroughputNormal be “the throughput is between 100kbps and 500 kbps”. Let Functioning(y) be “y is functioning normally”.
∀x (ThroughputNormal ∧(ProxyServer(x)∧ ¬Diagnostic(x))) → (∃y Router(y)∧Functioning(y))
The sample space is:
(1, 1); (1, 2) - sum of 3; (1, 3); (1, 4); (1, 5) - sum of 6; (1, 6);
(2, 1) - sum of 3; (2, 2); (2, 3); (2, 4) - sum of 6; (2, 5); (2, 6);
(3, 1); (3, 2); (3, 3) - sum of 6; (3, 4); (3, 5); (3, 6) - sum of 9;
(4, 1); (4, 2) - sum of 6; (4, 3); (4, 4); (4, 5) - sum of 9; (4, 6);
(5, 1) - sum of 6; (5, 2); (5, 3); (5, 4) - sum of 9; (5, 5); (5, 6);
(6, 1): (6, 2); (6, 3) - sum of 9; (6, 4); (6, 5); (6, 6)
Answer:
The most likely answer would be 282,240.
Step-by-step explanation:
I got a different value than the choices you've given me. But if 282,240; 14; and 21 are your only options, then the most likely answer would be 282,240. Any number followed by an exclamation point means that it will be multiplied by all whole numbers from 1 to that number. For example, 4! would be 1 * 2 * 3 * 4 = 24. In this problem, 7! equals 5,040; 8! equals 40,320; 
= 
; and 9! = 362,880. You can tell by the listed numbers that the product will be extremely big despite the fraction, so the best choice to go with would be 282,240.
Answer:
5/2
Step-by-step explanation:
Y(2)-Y(1)/ X(2)-X(1)
(27-2)/(1-(-9)
25/10
simplified=5/2
