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1 year ago

Question Solve. 2 1/3−1/2x=−2/3 Enter your answer in the box.

Mathematics

1 answer:

Tcecarenko [31]1 year ago

6 0

2/3 - 1/2x = -2/3 then the value of x is 6 .

The algebraic expression should often take one of the following forms: addition, subtraction, multiplication, or division. Bring the variable to the left and the remaining values to the right to determine the value of x. To determine the outcome, simplify the values.

The steps to use the calculator to determine x's value are as follows:

Fill in the multiplicand and product fields with the numbers (Integer/Decimal Numbers).
To obtain the result, press the "Solve" button now.
The output field will show the dividend or the x value.

given equation is

2/3 - 1/2x = -2/3

⇒7/3-x/2 = -2/3

⇒7/3+ 2/3 =x/2

⇒9/3 = x/2

⇒ x=3 x 2

⇒ x=6

therefore the value of the x is 6

To know more about how to find x values visit :

brainly.com/question/21481562

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What is it you need? If it's the equation: P=.75+7.95.

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3 years ago

I’m lost again can somebody help asap ??

serious [3.7K]

Fully detailed and equipped information process right below. The answer for this question is "25" (simplified form).

$\mathbf{2^{28} \times \Bigg(\dfrac{5^{- 2}}{2^3} \Bigg)^4 \times \Bigg(5^{- 5} \times 2^8 \times 1 \Bigg)^{- 2}}$

$\mathbf{2^{28} \times \Bigg(\dfrac{5^{- 2}}{2^3} \Bigg)^4 \times \Bigg(2^8 \times 1 \times \dfrac{1}{5^5} \Bigg)^{- 2}}$

$\mathbf{2^{28} \times \Bigg(\dfrac{5^{- 2}}{2^3} \Bigg)^4 \times \Bigg(1 \times \dfrac{2^8 \times 1}{5^5} \Bigg)^{- 2}}$

$\mathbf{2^{28} \times \Bigg(\dfrac{5^{- 2}}{2^3} \Bigg)^4 \times \Bigg(1 \times \dfrac{256}{3125} \Bigg)^{- 2}}$

$\mathbf{2^{28} \times \Bigg(\dfrac{5^{- 2}}{2^3} \Bigg)^4 \times \Bigg(\dfrac{3125}{256} \Bigg)^2}$

$\mathbf{2^{28} \times \Bigg(\dfrac{5^{- 2}}{2^3} \Bigg)^4 \times \dfrac{3125^2}{256^2}}$

$\mathbf{2^{28} \times \Bigg(\dfrac{1}{2^3 \times 5^2} \Bigg)^4 \times \dfrac{3125^2}{256^2}}$

$\mathbf{2^{28} \times \Bigg(\dfrac{1^4}{(2^3 \times 5^2)^4} \Bigg) \times \dfrac{3125^2}{256^2}}$

$\mathbf{2^{28} \times \Bigg(\dfrac{1^4}{(5^2)^4 \times (2^3)^4} \Bigg) \times \dfrac{3125^2}{256^2}}$

$\mathbf{2^{28} \times \dfrac{1}{2^{12} \times 5^8} \times \dfrac{3125^2}{256^2}}$

$\mathbf{\dfrac{3125^2 \times 1 \times 2^{28}}{256^2 \times 5^8 \times 2^{12}}}$

$\mathbf{\dfrac{2^{(28 - 12)} \times 3125^2}{256^2 \times 5^8}}$

$\mathbf{\dfrac{2^{16} \times 3125^2}{256^2 \times 5^8}}$

$\mathbf{\dfrac{2^{16} \times (5^5)^2}{(2^8)^2 \times 5^8}}$

$\mathbf{\dfrac{2^{16} \times 5^{10}}{2^{16} \times 5^8}}$

$\mathbf{\dfrac{2^{16} \times 5^{10 - 8}}{2^{16}}}$

$\mathbf{\dfrac{5^{10 - 8}}{1}}$

$\mathbf{\therefore \quad 5^2}$

$\mathbf{\therefore \quad 25}$

$\boxed{\mathbf{\underline{\therefore \quad Final \: \: Answer \: \: is: \: 25}}}$

Hope it helps.

7 0

3 years ago

Is 115 divided by 17 6 remainder 7?

Reika [66]

Answer:

Yes

Step-by-step explanation:

115 ÷ 17 = 6.7647

you can also round it up to 6.8

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2 years ago

Which equation is equivalent to x + 8 = 21?

pickupchik [31]

Answer:

Step-by-step explanation:

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3 years ago

Read 2 more answers

What is the center of MN given M(3, -1) and N(7,-5)

Neko [114]

Answer:

(5, -3)

Step-by-step explanation:

So the center of the two points, or a line can be defined using the equation: $midpoint=(\frac{x_2+x_1}{2}, \frac{y_2+y_1}{2})$ . So using the two points you gave, you simply plug the values in to get

$midpoint=(\frac{3+7}{2}, \frac{-1+(-5)}{2})\\$

Add numerators:

$midpoint=(\frac{10}{2}, \frac{-6}{2})$

Simplify fraction:

$midpoint=(5, -3)$

3 0

2 years ago