Answer:
A sample of 499 is needed.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of 
, and a confidence level of 
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of 
.
The margin of error is given by:
In this question, we have that:
90% confidence level
So 
, z is the value of Z that has a pvalue of 
, so 
.
How large a sample would be required in order to estimate the fraction of tenth graders reading at or below the eighth grade level at the 90% confidence level with an error of at most 0.03
We need a sample of n, which is found when 
. So
Rounding up
A sample of 499 is needed.
Answer:
x = -4/3
Step-by-step explanation:
8^(x+3)=32
2^3 = 8
2^5 = 32
3( x + 3 ) = 5
3x + 9 = 5
3x = -4
x = -4/3
Tell me if I am wrong.
Can I get brainliest
This is telling you to do area and then add the two numbers you get
<h3>Sample space = {a,b,c,d,e,f}</h3><h3>Event space = {a,c}</h3>
We simply list all of the letters mentioned as they are the possible outcomes. We can only pick one item from the sample space. The event space is the set of outcomes where we want to happen (picking either an 'a' or 'c').
Answer:
64.96
Step-by-step explanation:
The most common benchmark percents are 
and 
We are given 
which is closest to 
.
Now we calculate 
which is equal to 
.
We are left with 
more to add.
We can say 
Therefore 
Now add the two.
Thus 64.96 is the answer.
