3 divided by 1/6????

11. The student council is comparing prices for their semi-formal dance. They compare banquet. Hall A charges $40 per person. Ha

Natalka [10]

Answer:

TC (A) = 40x , TC (B) = 500 + 20x

Step-by-step explanation:

Let the number of students be = x

Hall A Total Cost

Relationship Equation, where TC (A) = f (students) = f (x) 40 per person (student) = 40x

Hall B Total Cost

Relationship Equation, where TC (B) = f (students) = f (x) 500 fix fee & 20 per person (student) = 500 + 20x

4 0

3 years ago

Given m||n, find the value of x.<br> +<br> (7x-7)°<br> m<br> (6x+11)°

KengaRu [80]

Answer:

x = 18

Step-by-step explanation:

$(7x - 7) \degree = (6x + 11) \degree \\ (exterior \: alternate \: \angle s) \\ \\ 7x - 7 = 6x + 11 \\ \\ 7x - 6x = 11 + 7 \\ \\ x = 18$

5 0

3 years ago

Andrea is a teacher. Her annual salary is $59,605. Her salary is dispersed to her semimonthly from September – June (10 months).

Brilliant_brown [7]

Answer:

don't know trying to get the ANSWER

7 0

3 years ago

BRAINLIEST ANSER!!! HELP ME ASAP!!! PLEASSEEE! determine the volume of a cylindrical bucket if the diameter is 8.5 inches and th

yarga [219]

The answer should be 652.2

8 0

4 years ago

In 2008, the average household debt service ratio for homeowners was 13.2. The household debt service ratio is the ratio of debt

ankoles [38]

Answer:

$t=\frac{13.88-13.2}{\frac{3.14}{\sqrt{44}}}=1.436$

$df=n-1=44-1=43$

$p_v =P(t_{(43)}>1.436)=0.079$

We see that the p value i higher than the significance level so then we FAIL to reject the null hypothesis and we can conclude that the true mean is not significantly higher than 13.2 *the value of 2008 ).

Step-by-step explanation:

Information given

$\bar X=13.88$ represent the sample mean

$s=3.14$ represent the sample standard deviation

$n=44$ sample size

$\mu_o =13.2$ represent the value that we want to test

$\alpha=0.05$ represent the significance level

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test

Hypothesis to test

We want to conduct a hypothesis in order to check if the true mean has increased from 2008 , and the system of hypothesi are:

Null hypothesis: $\mu \leq 13.2$

Alternative hypothesis: $\mu > 13.2$

The statistic for this case is:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

Calculating the statistic

Replacing the info given we got:

$t=\frac{13.88-13.2}{\frac{3.14}{\sqrt{44}}}=1.436$

P-value

The degrees of freedom are:

$df=n-1=44-1=43$

Since is a right tailed test the p value is:

$p_v =P(t_{(43)}>1.436)=0.079$

Decision

We see that the p value i higher than the significance level so then we FAIL to reject the null hypothesis and we can conclude that the true mean is not significantly higher than 13.2 *the value of 2008 ).

8 0

4 years ago