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3 years ago

3 divided by 1/6????

Mathematics

1 answer:

weeeeeb [17]3 years ago

5 0

Answer:

Step-by-step explanation:

3/1 x 6/1 = 18/1 = 18

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Place pi squared, 10, and square root of 70 in least to greatest

Nutka1998 [239]

Answer:

squaare root of 70<pi squared<10

Step-by-step explanation:

Talking about square root of 70, you can take the answer by approximation. u know square of eight is sixty four and square of nine is eighty one. so 70's square root shluld be between eight and nine. And as the value of pi is 3.14... when square of pi is considerd it should be >9 but <10 as pi>3. So 10 become te greatest

3 0

3 years ago

Write two division expression s that have the same vaule as 36.8 ÷ 2.3

Triss [41]

<h3>Write two division expression s that have the same vaule as 36.8 ÷ 2.3 </h3>

$32 \div 2 = 16\\\\48 \div 3 = 16$

Solution:

Given that,

We hve to find the two division expression s that have the same vaule as 36.8 ÷ 2.3

From given,

$36.8 \div 2.3 = 16$

So, we have to find two division expressions that has a value of 16

First division expression

We know that 32 divided by 2 gives 16

Thus, we can write as,

$32 \div 2 = 16$

Second Expression:

We know that 48 divided by 3 gives 16

Thus, we can write as,

$48 \div 3 = 16$

Thus the two expressions are found

7 0

3 years ago

Write the missing power of 10 in each equation.

Mrac [35]

1. 10 or 10 to the first power
2. 10000 or 10 to the fourth power
3. 100 or 10 to the second power
4. 1000 or 10 to the third power

7 0

2 years ago

I need help thank you

erma4kov [3.2K]

Answer:

≈ 5

Step-by-step explanation:

You can use the Pythagorean Theorem to solve this:

$a^{2} + b^{2} = c^{2}$

Now plug in the numbers into the formula:

$6^{2} + b^{2} = 8^{2}$

36 + $b^{2}$ = 64

Subtract 36 from both sides:

36 + $b^{2}$ = 64

-36 -36

_________

$b^{2}$ = 28

Square both sides:

$\sqrt{b^2} = \sqrt{28}$

b = 5.29

b ≈ 5

4 0

3 years ago

Given that g(x)=3x²-5x+7 find the following: g(-x)

AURORKA [14]

G(x) = 3x² - 5x + 7
g(-x) = -(3x² - 5x + 7)
g(-x) = -3x² + 5x - 7

This equation cannot be solved because of a few reasons,

1. This equation didn't show that it equals to 0.
2. Even if it equals to zero, square root of a negative number cannot be solved.
(I will show you what I mean)

-3x² + 5x - 7
is the same as
3x² - 5x + 7
by shifting the equation,

for example,
1 - 3 = -2
shifting other side
2 = -1 + 3

using 3x² - 5x + 7 to solve,

$Solve\ using\ the\ formular\ \ \boxed{ x= { \frac{-b \pm \sqrt{b^2-4ac} }{2a} } }$
a = 3
b = -5
c = 7
$x= { \frac {-(-5) \pm \sqrt{ (-5)^2-4(3)(7) } }{2(3)} }$
$x= { \frac {5 \pm \sqrt{-59} }{6} }$

∴This equation cannot be solved.

5 0

3 years ago