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3 years ago

What is 6.338 rounded to the nearest hundredth

Mathematics

1 answer:

azamat3 years ago

3 0

Answer:

6.34

Step-by-step explanation:

brainliest pleassse

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This is the question

zysi [14]

Answer:(1,1)

Step-by-step explanation:

Its asking where both linear and curve lines are being hit,

(fxg)(0)= 1,1

3 0

3 years ago

QUESTION 1<br> Calculate the volume<br> 5 cm<br> 6 cm<br> 8 cm

Masteriza [31]

Step-by-step explanation:

Volume = l * b * h

$volume \: = 5 \times 6 \times 8 \\ = 240 \: cm^{3}$

3 0

3 years ago

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How should they divide the money so that each class gets the same fraction of the prize money as the fraction of the box tops th

bija089 [108]

Figure the fraction of box tops each class collected, then multiply the prize money by that fraction.

Total box tops = 3760 +2301 +1855 = 7916

Mr Coronado's class's fraction: 3760/7916 × $600 = $284.99

Mrs De Souza's class's fraction: 2301/7916 × $600 = $174.41

Mr Nost's class's fraction: 1855/7916 × $600 = $140.60

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3 years ago

In circle Y, what is mTU?

Marat540 [252]

we know that

The measure of the interior angle is the half-summit of the arcs that comprise it and its opposite

$63=\frac{1}{2} *(arc \ SR+arc\ TU)\\ \\ 126=55+arc\ TU\\ \\ arc\ TU=126-55\\ arc\ TU=71\ degrees$

therefore

the answer is

the measure of arc TU is equal to $71\ degrees$

4 0

3 years ago

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WILL GIVE BRAINLIEST A rocket is launched vertically from the ground with an initial velocity of 64. Write a quadratic function

tiny-mole [99]

Answer:

$h=64t-4.9t^{2}$

Please refer to the attached graph.

Step-by-step explanation:

Given that

Initial velocity of rocket = 64 and is launched vertically.

To find:

Quadratic equation in time to represent the height of rocket in feet.

Solution:

Unit of initial velocity is not given in the question statement, let the velocity be in feet/second only.

Initial velocity, u = 64 feet/s

The acceleration will be = -g because it is going opposite to gravitational force so it will be negative acceleration motion (speed will be decreasing) so -g will be the acceleration.

Formula for distance traveled is given as:

$s=ut+\dfrac{1}{2}at^2$

Here Let us represent s by 'h'

a = -g = 9.8 m/ $s^2$

Let us put the known values in the formula:

$h=64t+\dfrac{1}{2}(-9.8)t^2\\\Rightarrow h =64t-4.9t^2$

It is a quadratic equation, the equation represents the graph of a parabola.

Please refer to the attached graph.

Value of height is 0 at 0 second and ~13 seconds

6 0

3 years ago