The problem is an arithmetic sequence with:
a₁ = 206,300
an = 208,400
n = 2013 - 2000
n = 13
To find the annual increase, use this following formula
an = a₁ + d(n - 1)
d represents the annual increase
Input the numbers
an = a₁ + d(n - 1)
289,400 = 206,300 + d(13 - 1)
289,400 = 206,300 + 12d
289,400 - 206,300 = 13d
83,100 = 12d
12d = 83,100
d = 83,100/12
d = 6,925
The annual increase is $6925
The answer is B..........................................................
P = k/w^2
<span>first of all you need to find k </span>
<span>But I kind of don't like the units of each value so let say </span>
<span>400KPa = 4 * 10^5 Pa = 4 * 10^5 N/m^2 </span>
<span>2 cm = 2 * 10^-2 m </span>
<span>input values in the equation </span>
<span>4*10^5 = k/(4*10^-4) >>> k = 160 N </span>
<span>P = 160/w^2 </span>
<span>it said if she wears a heel with a width of .5 cm </span>
<span>P = 160(0.5 * 10^-2)^2 >>> P = 6400 KPa</span>
