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levacccp [35]
1 year ago
12

-26 - 4m = -2(2m + 13)

Mathematics
1 answer:
forsale [732]1 year ago
3 0

We have to solve for m:

\begin{gathered} -26-4m=-2(2m+13) \\ -2(13+2m)=-2(2m+13) \\ -2=-2 \end{gathered}

m can take any value as this equation is an identity.

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Fiesta28 [93]
I think it’s A pretty sire
5 0
3 years ago
Chipper had 189 hits in 572 at bats calculate chippers batting average for season by dividing the number if hits by the number o
lord [1]

Answer:

0.330

Step-by-step explanation:

Divide the number of hits (189) by the number of bats (572)

189/572=0.330

8 0
3 years ago
300 mi /20 sec = ? Mi /1 min
snow_lady [41]

Answer:

900

Step-by-step explanation:

To get your answer, you can just multiply 20 seconds by 3 to get 60 seconds, which is a minute.

Since whatever you do on one side you have to do to the other, multiply 300 mi by 3 as well. That would get you 900.

4 0
3 years ago
Brenda throws a dart at this square-shaped target: Part A: Is the probability of hitting the black circle inside the target clos
Masteriza [31]
Either way.  The probability of hitting the circle is:

P(C)=Area of circle divided by area of square

P(W)=(area of square minus area of circle divided by area of square

P(C)=(πr^2)/s^2

P(W)=(s^2-πr^2)/s^2

...

Okay with know dimensions, r=1 (because r=d/2 and d=2 so r=1), s=11 we have:

P(inside circle)=π/121  (≈0.0259  or 2.6%)

P(outside circel)=(121-π)/121  (≈0.9744 or 97.4%)
6 0
3 years ago
A family has two cars. the first car has a fuel efficiency of 40 miles per gallon of gas and the second has a fuel efficiency of
Aliun [14]
Let x and y represent the numbers of gallons used by the 40 mpg and 35 mpg cars, respectively.
.. x +y = 40 . . . . . . . . . . .total consumption is 40 gallons
.. 40x +35y = 1525 . . . . total miles driven = 1525

Multiply the first equation by 40 and subtract the second.
.. 40(x +y) -(40x +35y) = 40(40) -(1525)
.. 5y = 75
.. y = 15
.. x = 40 -15 = 25

The 40 mpg car consumed 25 gallons.
The 35 mpg car consumed 15 gallons.
7 0
3 years ago
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