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ankoles [38]
3 years ago
15

Average of 6 numbers is 4, if the average of 2 numbers is 2 what is the average of other 4

Mathematics
1 answer:
RideAnS [48]3 years ago
4 0

Answer:

5

Step-by-step explanation:

Let's just pretend the 6 numbers are: a,b,c,d,e,f.

Then (a+b+c+d+e+f)/6 =4 (given by first statement.)

Let's pretend the average of 2 numbers is 2 means they are talking about the a and b.

So (a+b)/2=2.

Now we want to find (c+d+e+f)/4 as requested by their question.

So first step multiply both sides of our first equation by 6 giving us:

a+b+c+d+e+f=24

So the second step multiply both sides of our second equation by 2 giving us:

a+b=4.

Now if a+b+c+d+e+f=24 and a+b=4, then c+d+e+f=20 since 20+4=24.

So the average of the four numbers c,d,e, and f is 20/4=5.

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2 years ago
Type the correct answer in the box
TiliK225 [7]

The expression of X in terms of l is X = √5 l

<h3>How to calculate the diagonal of a rectangle</h3>

According to the given information:

  • Length = w
  • If length<u> l is twice as long </u>as the width, then l = 2w

Determine the diagonal using the Pythagoras theorem:

X² = w²+(2w)²
X² = w² + 4w²

X =√5w²
X = √5 w

Replace w with l

X = √5 l

Hence the expression of X in terms of l is X = √5 l

Learn more on diagonals here: brainly.com/question/26154016

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3 years ago
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Answer: $11,600

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48 = x

y = 200(48) + $2,000

y = $9,600 + $2,000

y = $11,600

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X divided by the 4th root of x^9
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Answer:

7

Step-by-step explanation:

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